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2 years ago

Which type of study best describes the following research most likely to be done?

Mathematics

2 answers:

never [62]2 years ago

7 0

Answer:

In this case the Teacher is carrying out an experimental estudy.

Step-by-step explanation:

In this case, the Teacher is carrying out an experimental study. Because three things make it an experiment. First, the teacher puts the test to all of her students. Without sampling or choosing a representational population. She controls the conditions the students undergo and she also hey are recorded. So her manipulation of the environment separates it from observation. Also, she practices the study in all of them so there is no simulation all data is real. Thus, an Experimental study is a correct answer. She runs tests o all of them without asking any question discarding census.

vichka [17]2 years ago

5 0

Answer:

simulation study

Step-by-step explanation:

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Justify each step x/3-7=11 x/3=18 x=6

Schach [20]

This is the steps for equation solving for the value of x,

x/3-7 = 11

now 7 goes to the other side of equation by changing the sign from - to +,

x/3 = 11 + 7

x/3 = 18

now when we multiply both sides of equation with 3 or 3 goes to the other side of equation and multiply with 18 leaving x alone here for finding the value of x,

and we get, x = 54

at the end of equation we get x = 54, if the equation was in the form 3x - 7 = 11, then we will get x = 6

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3 years ago

In ABC, if m find the measure of each angle.

monitta

Answer:

Let the angles have measures 2x,3x,4x

Then 2x+3x+4x = 180

and the rest is easy

Step-by-step explanation:

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2 years ago

A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = −16t2 + 48t where t equals the

zlopas [31]

1. The function $h(t)=-16t^{2}+48t$ is a parabola of the form $ax^{2}+bx$ . The the formula for the axis of symmetry of a parabola is $x= \frac{-b}{2a}$ . We can infer from our function that $a=-16$ and $b=48$ , so lets replace those values in our formula:
$x= \frac{-b}{2a}$
$x= \frac{-48}{-2(16)}$
$x= \frac{-48}{-32}$
$x= \frac{3}{2}$
$x=1.5$
We can conclude that to the left of the line of symmetry the ball is reaching its maximum height, and to the right of the line of symmetry the ball is falling.

2. Lets check how much time the ball takes to reach its maximum height and return to the ground. To do that we are going to set the height equal to zero:
$0=-16t^{2}+48t$
$-16t(t-3)=0$
$t=0$ or $t-3=0$
$t=0$ or $t=3$
From our previous point we know that the ball reaches its maximum time at $t=1.5$ , which means that it takes 1.5 seconds to reach the maximum height and 1.5 seconds to fall back to the ground.

7 0

3 years ago

Read 2 more answers

4×3-(2×3-16÷4) the answer with work

Reika [66]

Answer:

Step-by-step explanation:

2x3=6

16/4=4

4x3-(6-4)

6-4=2

4x3-(2)

4x3=12

12-(2)

12-2=10

3 0

3 years ago

Read 2 more answers

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago