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Korvikt [17]
3 years ago
5

The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.

Mathematics
1 answer:
MariettaO [177]3 years ago
5 0
The line through that point and the origin has a slope of -1. It is perpendicular to the line you want, so the line you want has slope +1. Its equation can be written as
.. y = (x -4) -4
or, in standard form
.. x - y = 8

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Cot^2x csc^2x + 2 csc^2x –cot^2 = 2
kow [346]

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

cot² x + 2 = 2 sin² x + cos² x

Pythagorean identity:

cot² x + 2 = sin² x + 1

Subtract 1 from both sides:

cot² x + 1 = sin² x

Pythagorean identity:

csc² x = sin² x

Multiply both sides by sin² x:

1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

Which simplifies to:

x = π/2 + πk

4 0
3 years ago
Solve the linear equation. 8x+32=1/5(25x−15)−4x
Kipish [7]

Answer: x= 5

Step-by-step explanation:

8x+32=1/5(25x−15)−4x

8x + 32 = <u>25x -15</u> - 4x   <u><em>- 25x -15/  5</em></u>

                    5

8x + 32 = 5x -3 - 4x

8x + 4x - 5x = -32 - 3

7x =-35

x = 35/7

x= 5

5 0
3 years ago
What is the angular velocity of a 6–foot pendulum that takes 3 seconds to complete an arc of 14.13 feet? Use 3.14 for π.
irakobra [83]
The angular velocity is the linear speed divided by the radius.
  ω = d/(t*r) = (14.13 ft)/((3 s)*(6 ft))
  ω = 0.785 radians/second
There are 180/π degrees per radian, so the angular velocity can also be written as ...
  ω = 45 degrees/second
5 0
3 years ago
In order to pay for his expenses, Chuck needs to earn $2400 at least every
sleet_krkn [62]

Answer:

5400

Step-by-step explanation:

2400+3000

8 0
3 years ago
Which graph shows the solution set of <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx-1%7D%7Bx-3%7D%20%5C%20%20%5Ctextless%20%5C%2
forsale [732]

Answer:

Step-by-step explanation:

f(x) = (x - 1)/(x - 3) < 0

The critical points are x = 1 and x = 3

When x < 1, f(x) > 0

When 1 < x < 3,  f(x) < 0  

When x > 3,   f(x) > 0

Note  when x = 3 f(x) has no value and when x = 1 f(x) = 0.

I can't see all the graphs very well  but there should be a red line between 1 and 3 with a clear circle on x = 1 and x = 3.

Looks like its the last choice.

7 0
3 years ago
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