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melamori03 [73]
3 years ago
12

Copy and complete statement

Mathematics
1 answer:
irakobra [83]3 years ago
3 0

Answer:

sqrt(64) > 5

Step-by-step explanation:

sqrt(64) = 8; therefore

sqrt(64) > 5

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9 Calculator What is the median of the data set? 3, 10, 1, 6, 10, 3, 11, 14<br><br><br><br><br>​
Svetradugi [14.3K]

Answer:

1, 3, 3, 6, 10, 10, 11, 14

(6,10)  6+10= 16  

16/2= 8

median is = 8

Step-by-step explanation:

6 0
3 years ago
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
What is the median of this set of data: 593, 588, 540, 434, 420, 398, 390, 375
Anna [14]
C. 427

The median is the middle number of all the data

Since there is an even number of data points the median is in between the middle two data points (434 and 420)

To find this: 434-420=14
14/2=7
434-7=427
420+7=427
8 0
3 years ago
Every evening Jenna empties her pockets
rodikova [14]

Answer:

15

Step-by-step explanation:

1 dime = 10

1 quarter=25

x=number of coins - dimes

y= number of coins - quarters

x (10)+y(25)=10.25

x+y=50

x= 50-y

x(10)+y(25)=1025

(50-y)(10)+25y =1025

500-10y+25y=1025

500+15y=1025

15y= 1025 - 500

15y=525

y=525/15

y=35

x= 50-35=15

3 0
2 years ago
Please help asap, i need this!!!!!​
ololo11 [35]
Ch gc cdvnjhg if Gn havin ggcdhb gts Gn
7 0
3 years ago
Read 2 more answers
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