Ask question

Ask question

All categories

3 years ago

12

The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 246.9 and a standard deviation of 6

9.3 (All units are 1000 cells/l.) Using the empirical rule, find each approximate percentage below. a. What is the approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 177.6 and 316 2? b. What is the approximate percentage of women with platelet counts between 39.0 and 454.8? a. Approximately % of women in this group have platelet counts within 1 standard deviation of the moan, or between 177.6 and 316.2. (Type an integer or a decimal. Do not round.)

1 answer:

belka [17]3 years ago

3 0

Answer:

The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 177.6 and 316.2 is 68%.

The approximate percentage of women with platelet counts between 39.0 and 454.8 is 99.7%

Step-by-step explanation:

Mean : $\mu = 246.9$

Standard deviation : $\sigma = 0.49$

Empirical rule :

1 ) 68% of the data lies within 1 standard deviation of mean

This means 68% of data lies between: $\mu-\sigma$ to $\mu+\sigma$

2) 95% of the data lies within 2 standard deviation of mean

This means 95% of data lies between: $\mu-2\sigma$ to $\mu+2\sigma$

3) 99.7% of the data lies within 3 standard deviation of mean

This means 99.7% of data lies between: $\mu-3\sigma$ to $\mu+3\sigma$

Now to find the approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 177.6 and 316. 2

Use rule 1: $\mu-\sigma$ to $\mu+\sigma$

$246.9-69.3$ to $246.9+69.3$

$177.6$ to $316.2$

So, according to rule 1, 68% of the data lies within 1 standard deviation of mean i.e. 68% of the data lies between 177.6 and 316.2.

Now to find the approximate percentage of women with platelet counts between 39.0 and 454.8?

Use rule 3: $\mu-3\sigma$ to $\mu+3\sigma$

$\mu-3\sigma$ to $\mu+3\sigma$

$39$ to $454.8$

So, According to rule 3 : 99.7% of the data lies within 3 standard deviation of mean i.e. 99.7% of data lies between 39.0 and 454.8

You might be interested in

Help with this immediately

charle [14.2K]

x= 2

Step-by-step explanation:

The answer for what does x= is,

x = 2

6 0

4 years ago

2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?

mezya [45]

Answer:

the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

Step-by-step explanation:

We need to find inverse of the quadratic function $f(x) = x^2 - 3$

Let

$y=x^2-3$

Replace x and y

$x=y^2-3$

Now, we will solve for y

Adding 3 on both sides

$x+3=y^2-3+3$

$x+3=y^2$

Taking square root on both sides

$\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}$

Now replace y with $f^{-1}(x)$

$f^{-1}(x)=\pm \sqrt{x+3}$

So, the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

3 0

3 years ago

A question on a math test was to find the value of 15.12 divided by 2.4 Steve said the answer is 0.63 what mistake might Steve h

marusya05 [52]

Answer:

2.133333

Step-by-step explanation:

He didn't simplify it

7 0

3 years ago

Read 2 more answers

Joel takes out a loan with a stated rate of 11.85% interest. If the interest is calculated weekly, how much greater is Joel’s ef

Dmitry_Shevchenko [17]

Effective interest rate is
R=((1+0.1185÷52)^(52)−1)×100=12.57%

How much greater
12.57−11.85=0.72%

7 0

3 years ago

A circle has a diameter with endpoints at 15 + 25i and –25 – 17i. Which point is also on the circle?

Vanyuwa [196]

Answer:

The point 16+24i is the point satisfying the equation

Hence, Option D is correct.

Step-by-step explanation:

We will find mid-point from end points given.

Mid-point formula: $(x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

On substituting the values we will get:

$(x,y)=(\frac{-25+15}{2},\frac{-17+25}{2})$

$(x,y)=(-5,4)$

Now, we have general equation of circle:

$(x-a)^2+(y-b)^2=r^2$

We will find r that is distance from mid-point to end oint using distance formula

$\text{distance formula}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Here, $x_1=-5,x_2=-25,y_1=4,y_2=-17$

On substituting the values we get:

$\text{distance formula}=\sqrt{(-25+5)^2+(-17-4)^2}$

$\text{distance formula}=\sqrt({20}^2+{21}^2)$

$\text{distance}=\sqrt{841}$

Hence, $r^2=841$

Substituting the values in general equation we get:

$(x-(-5))^2+(y-4)^2=841$

[tex]\Rightarrow(x+5)^2+(y-4)^2=841[tex]

And when we substitute x=16 and y=24 the equation will be satisfied

and a=-5 and b=4

Hence, will lie on the circle

Therefore, option D is correct.

3 0

4 years ago

Read 2 more answers