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prisoha [69]
3 years ago
11

Multiply (FOIL) ( x - 3)( 2x + 5) (3x + 7)(2x - 1)

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

(x-3)(2x+5)=2x^2+5x-6x-15=\boxed{2x^2-x-15}\\\\(3x+7)(2x-1)=6x^2-3x+14x-7=\boxed{6x^2+11x-7}

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(6+√-64)(3-√-16) Multiply. This is urgent, please explain this to me!
romanna [79]

Answer:

50

Step-by-step explanation:

\sqrt{-64} and \sqrt{-16} can be expressed in complex form, with \sqrt{-1} = i

\sqrt{-64} = \sqrt{64(-1)} = \sqrt{64} × \sqrt{-1} = 8i

\sqrt{-16} = \sqrt{16(-1)} = \sqrt{16} × \sqrt{-1} = 4i

the factors can then be expressed as

(6 + 8i)(3 - 4i) ← expand using FOIL

= 18 - 24i + 24i - 32i² [ i² = (\sqrt{-1} )² = - 1 ]

= 18 - 24i + 24i + 32 ← collect like terms

= 18 + 32 + 0

= 50

6 0
2 years ago
Find the exact value of the following expression (without using a calculator): tan(Sin^-1 x/2)
Sati [7]

Answer:

tan(Sin^-1 x/2)=  \frac{x/2}{\sqrt{1-x^{2}/4 } }

Step-by-step explanation:

Let sin^-1 x/2= θ

then sinθ= x/2

on the basis of unit circle, we have a triangle with hypotenuse of length 1,   one side of length x/2 and opposite angle of θ.

          tan(Sin^-1 x/2) = tanθ

           tanθ= sinθ/cosθ

as per trigonometric identities cosθ= √(1-sin^2θ)

           tanθ= sinθ/ √(1-sin^2θ)

substituting the value sinθ=x/2 in the above equation

             tanθ= \frac{x/2}{\sqrt{1-x^{2}/4 } }

now substituting the value sin^-1 x/2= θ in above equation

             tan(sin^-1 x/2) =  \frac{x/2}{\sqrt{1-x^{2}/4 } }

!

3 0
3 years ago
Please help me branniest <br><br><br> Any answer without proof will be reported
Ghella [55]

There Is one solution because there only one point of the line that intercept.

4 0
3 years ago
Find 8 + 35 + (-76).
scZoUnD [109]
8 + 35 + (-76)
= 8 + 35 - 76
= 43 - 76
= -33 (answer)
7 0
3 years ago
Read 2 more answers
Measures of the two triangles DEF and PQR
Maurinko [17]

Answer:

Measures of the two triangles DEF and PQR

are shown in the figure. Check if the

triangles are congruent. If congruent, which

of the following statements is true? Justify.

∆ DEF ≅ ∆ PQR ;

∆ DEF ≅ ∆ QPR ;

∆ DEF ≅ ∆ RPQ. First to Answer with explanation will be marked as brainliest.

5 0
2 years ago
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