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prisoha [69]
3 years ago
11

Multiply (FOIL) ( x - 3)( 2x + 5) (3x + 7)(2x - 1)

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

(x-3)(2x+5)=2x^2+5x-6x-15=\boxed{2x^2-x-15}\\\\(3x+7)(2x-1)=6x^2-3x+14x-7=\boxed{6x^2+11x-7}

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4 years ago
Jug A has 0.1 litres more than jug B. Jug C has 200 millilitres less than jug B. Jug D has ¼ of the amount that is in jug A. The
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Answer:

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2. Jug C = B - 200 (or 0.2 litres)

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In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.  

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Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)

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