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3 years ago

Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}

Mathematics

1 answer:

quester [9]3 years ago

8 0

It is gonna be 12,7 because the question asking for what is the recursive

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Find the root of the quadratic equation y=3x^2-30x+45

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$y=3x^2-30x+45\\\\a=3;\ b=-30;\ c=45\\\Delta=b^2-4ac\\\\\Delta=(-30)^2-4\cdot3\cdot45=900-540=360 \ \textgreater \ 0\\\\therefore\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{360}=\sqrt{36\cdot10}=\sqrt{36}\cdot\sqrt{10}=6\sqrt{10}\\\\x_1=\dfrac{30-6\sqrt{10}}{2\cdot3}=\dfrac{30-6\sqrt{10}}{6}=\boxed{5-\sqrt{10}}\\\\x_2=\dfrac{30+6\sqrt{10}}{2\cdot3}=\dfrac{30+6\sqrt{10}}{6}=\boxed{5+\sqrt{10}}$

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What are the solutions to the quadratic equation (5y + 6)2 = 24?b

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Step-by-step explanation:

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3 years ago

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The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the

kipiarov [429]

Interquartile Range (IQR) = $Q_3-Q_1$ , with $Q_3$ as the upper quartile and $Q_1$ as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: $\{59,76,84,93,95,97,101,101,102,102,104,106\}$

Next, find the median:

$\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99$

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

$\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5$

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

$\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102$

Now that we have the upper and lower quartile, subtract them:

$102-88.5=13.5$

<u>In short, the IQR of this data set is 13.5.</u>

8 0

3 years ago

Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}​

Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}