Answer:
x = 5, -2
Step-by-step explanation:
basic format is ax^2 + bx + c. multiply ac and ask urself what # + what is equal to b? those two same numbers should also multiply to get you ac.
x^2 - 3x - 10 = 0
(x-5) (x+2) = 0
x - 5 = 0 and x + 2 = 0
x = 5 and x = -2
So in this case a= 1 and c = -10. -10 x 1 = -10. -5 x 2 is equal to -10 and -5 + 2 gets you -3, which is b.
I don't think I explained it very well but I hope that helps a little :)
If it says 3×8 its like saying 8+8+8=21.
It's just a faster way of adding.
Anything multiplied by 0 is 0.
Anything multiplied by 10 just add a 0 to the end of the number example 10×2=20.
9. 0.26666
10. 2.375
11. 7/20
12. 206111/<span>50000</span>
Answer:
$$\sqrt[3]{27x^6y^4}=3 x^2\sqrt[3]{y^4}$$
Step-by-step explanation:
![\sqrt[3]{27x^6y^4}= \sqrt[3]{3^3x^6y^4}\\\sqrt[3]{27x^6y^4}=\sqrt[3]{3^3} \sqrt[3]{x^6} \sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E6y%5E4%7D%3D%20%5Csqrt%5B3%5D%7B3%5E3x%5E6y%5E4%7D%5C%5C%5Csqrt%5B3%5D%7B27x%5E6y%5E4%7D%3D%5Csqrt%5B3%5D%7B3%5E3%7D%20%5Csqrt%5B3%5D%7Bx%5E6%7D%20%5Csqrt%5B3%5D%7By%5E4%7D)
therefore,
![\sqrt[3]{27x^6y^4}=3 x^2\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E6y%5E4%7D%3D3%20x%5E2%5Csqrt%5B3%5D%7By%5E4%7D)
C I know I saw that on my phone
