Answer:
23 Yards
Step-by-step explanation:
So for this question, we would have to start off with writing an equation: 19.71+0.23x=25 once we subtract 19.71 on both sides, the left over sum of money will be 5.29. Since we are dealing with BOTH Dollars and Cents, it should be remembered to use 23 CENTS instead of Dollars.
= 23 so the finals answer is 23 yards.
Answer:
Switch .91 and .19 and you're good
Step-by-step explanation:
Answer:
21
Step-by-step explanation:
I shall change the pictures to letters
a + a + b = 40 --(1)
b - c = 7 --(2)
c + a = 19 --(3)
a - c + b = ?
From (1):
2a + b = 40
b = 40 - 2a --(4)
From (2):
b = 7 + c --(5)
Sub (4) into (5):
40 - 2a = 7 + c
c = 33 - 2a --(6)
Sub (6) into (3):
33 - 2a + a = 19
a = 14
Sub a = 14 into (4) and (6):
b = 40 - 2(14) = 12
c = 33 - 2(14) = 5
therefore, a - c + b = 14 - 5 + 12 = 21
Topic: simultaneous equations
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Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90



has a pvalue of 0.9649
X = 82



has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
The answer is: " 2 :5 " ; or, write as: " 2/5 " .
________________________________________________________
The ratio of 'girls' to 'all students' is: "2: 5 " ; or, write as: " 2/5 ".
________________________________________________________
Explanation:
________________________________________________________
Given: The ratio of boys to girls is: " 3:2 " .
Problem: Find the ratio of "girls" to "all students:
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Note: This ratio of "boys to girls", which is " 3 : 2 " ;
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→ can be expressed as " 3x: 2x" ;
in which the total number of students is: " 3x + 2x " = 5x " .
→ The total number of students is represented as: " 5x " .
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→ The ratio of "girls to boys" is: "2x : 3x" .
→ {that is; the "inverse" of the ratio of "boys to girls"} ;
→ {that is; the "inverse" of " 3x: 2x" } ; → which is: " 2x : 3x " .
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The ratio of "girls" to "all students" is: "2x : 5x " ; or " 2x/5x " ;
→ Both "x" values cancel ; {since: " x/x = 1 "} ;
_________________________________________________________
→ and we have the answer: " 2 :5 " ; or, write as: " 2/5 " .
_________________________________________________________
The ratio of 'girls' to 'all students' is: " 2 :5 " ; or, write as: " 2/5 ".
_________________________________________________________