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2 years ago

Help please! What is 438 x 934? I'm timed (gc for the school peeps sending this to them)

Mathematics

1 answer:

KatRina [158]2 years ago

3 0

Answer:

438 x 934=409092

Step-by-step explanation:

I hope this helps.

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Find the value of x for which line a is parallel to line b.

mote1985 [20]

Answer:

A. $x=34^o$

Step-by-step explanation:

We have been given a graph of two parallel lines and we are asked to find the value of x.

We can see that angle that measure x and the angle that measure 34 degrees is inside our parallel lines a and b and on the opposite side of transversal, so these angles are alternate interior angles.

Since the alternate interior angles are equal, therefore, value of x is 34 degrees and option A is the correct choice.

7 0

3 years ago

The length of the hypotenuse of the right triangle is 25 cm, the length of one of the legs is 10 cm. What is the length of the s

sergejj [24]

Answer:

$\large\boxed{AD=21\ and\ CD=2\sqrt{21}}$

Step-by-step explanation:

Look at the picture.

Use the Pythagorean theorem for calculate the length of CA:

$CA^2+CB^2=AB^2$

We have

$CA=x,\ CB=10,\ AB=25$

Substitute:

$x^2+10^2=25^2$

$x^2+100=625$ subtract 100 from both sides

$x^2=525\to x=\sqrt{525}\\\\x=\sqrt{25\cdot21}\\\\x=\sqrt{25}\cdot\sqrt{21}\\\\x=5\sqrt{21}\ cm$

ΔADC and ΔACB are similar. Therefore the corresponding sides are in proportion:

$\dfrac{AD}{AC}=\dfrac{AC}{AB}$

We have:

$AD=y,\ AC=5\sqrt{21},\ AB=25$

Substitute:

$\dfrac{y}{5\sqrt{21}}=\dfrac{5\sqrt{21}}{25}$

$\dfrac{y}{5\sqrt{21}}=\dfrac{\sqrt{21}}{5}$ cross multiply

$5y=5(\sqrt{21})^2$ divide both sides by 5

$y=21\ cm$

If you mean the length of segment CD, then use the proportion:

$\dfrac{CD}{AD}=\dfrac{CB}{CA}$

Substitute:

$\dfrac{CD}{21}=\dfrac{10}{5\sqrt{21}}\\\\\dfrac{CD}{21}=\dfrac{2}{\sqrt{21}}\qquad\text{cross multiply}\\\\CD\sqrt{21}=42\qquad\text{multiply both sides by}\ \sqrt{21}\\\\21CD=42\sqrt{21}\qquad\text{divide both sides by 21}\\\\CD=2\sqrt{21}\ cm$