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icang [17]
2 years ago
12

What's the area of this rectangular prism?

Mathematics
2 answers:
zalisa [80]2 years ago
8 0

Answer:

The answer 146cm Hope his helps.

Step-by-step explanation:

Hitman42 [59]2 years ago
5 0

Answer: 146cm²

Step-by-step explanation:

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2/3 divided by 5 please help me I'm bad at math (it needs to be a fraction)
Viefleur [7K]

Answer:

The answer is 4

Step-by-step explanation: I did the work and it works out like that I hope this helps

3 0
3 years ago
ADHE - ADGF below. Find the value of 'x'.<br> X<br> H н<br> E<br> 8<br> 2.<br> 12
Vlad1618 [11]

Given:

\Delta DHE\sim \Delta DGF

To find:

The value of x.

Solution:

We know that, corresponding sides of similar triangles are proportional.

Since,\Delta DHE\sim \Delta DGF, therefore

\dfrac{HE}{GF}=\dfrac{DE}{DF}

On substituting the values from the figure, we get

\dfrac{8}{12}=\dfrac{x}{x+2}

\dfrac{2}{3}=\dfrac{x}{x+2}

On cross multiplication, we get

2(x+2)=3x

2x+4=3x

4=3x-2x

4=x

Therefore, the value of x is 4.

8 0
2 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
2 years ago
F(x)=2x^2+3 and g(x)=x^2-7 find (f+g)(x)
defon

Answer:

3x^2 -4

Step-by-step explanation:

F(x)=2x^2+3 and g(x)=x^2-7

(f+g)(x) =

We add the two functions together

(f+g)(x) =2x^2+3+x^2-7

I like to line them up vertically

(f+g)(x) =

2x^2 +3

+x^2  -7

------------------

3x^2 -4

3 0
2 years ago
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
3 years ago
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