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3 years ago

What is the standard deviation of the following data set?

Mathematics

1 answer:

tia_tia [17]3 years ago

4 0

Answer:

D. 14.32

Step-by-step explanation:

The formula for standard deviation is:

$SD = \sqrt{\frac{\sum | x-\mu|^2}{N}}$

The mean μ is 33.

The (x minus μ) squared are 361, 49, 49, 361 respectively.

So that the SD = $\sqrt{\frac{820}{4}} \approx 14.31782...$

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Use the intermediate value theorem to choose an interval over which the function, f(x)=2x^3 - 3x +5 is guaranteed to have a zero

Sergio039 [100]

Answer:

The answer is c. {0,2).

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Selmas class making a care package to give to victims of a natural disaster.Selma packs one box in 5 minutes and has already pac

bixtya [17]

Each of them need to work 105 minutes more in order to have packed the same number of boxes.

Explanation

Suppose, they need to work for $x$ minutes more in order to have packed the same number of boxes.

Selma packs one box in 5 minutes and Trudy packs one box in 7 minutes.

So, the number of boxes packed by Selma in that $x$ minutes $=\frac{x}{5}$ and the number of boxes packed by Trudy in $x$ minutes $=\frac{x}{7}$

Given that, Selma and Trudy have already packed 12 and 18 boxes.

Now if each of them packed the same number of boxes, then the equation will be......

$12+\frac{x}{5}=18+\frac{x}{7}\\ \\ \frac{x}{5}-\frac{x}{7}= 18-12\\ \\ \frac{7x-5x}{35}=6\\ \\ \frac{2x}{35}=6\\ \\ 2x= 210\\ \\ x= \frac{210}{2}=105$

So, each of them need to work 105 minutes more in order to have packed the same number of boxes.

6 0

3 years ago

Obtain the total salary?)

Nonamiya [84]

Answer:

F(d) = 30 + 0.50d

Step-by-step explanation:

Given

Charges = P8.00 ---- first 4 km

Additional = P0.50

Required

Write a function to address the scenario.

Represent the whole distance covered with d.

First,we need to determine the total charges for the first four hours.

Charges = 8.00 * 4

Charges = 32.00

Next, we determine the charges for additional distance.

Charges = 0.50 * (d - 4)

d - 4 is the remaining distance after the first 4.

Charges = 0.50d - 2

The function is then written as;

F(d) = 32 + 0.50d - 2

F(d) = 32 - 2 + 0.50d

F(d) = 30 + 0.50d

8 0

3 years ago

For which independent value do the equations generate the same dependent value? y1=6x-16 , y2=3x-10

Nikitich [7]

The question asks which x-value gives the same y-value for both equations, so if you need the ys to be equal, you can set both equations equal to each other, giving you 6x-16=3x-10. Now, solve for x. 6x-16=3x-10, subtract 3x and add 16, 3x=6, divide 3, x=2. Your answer is x=2.

7 0

3 years ago

We have seen that isosceles triangles have two sides of equal length. The angles opposite these sides have the same measure. Use

Naddik [55]

Question has missing figure, the figure is in the attachment.

Answer:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

Step-by-step explanation:

Given,

We have an isosceles triangle which we can named it as ΔABC.

In which Length of AB is equal to length of BC.

And also m∠B is equal to m∠C.

ext.m∠C= 115°(Here ext. stands for exterior)

We have to find the measure of angles angles 1 through 5.

Solution,

For ∠1.

∠1 and ext.∠C makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle1+ext.\angle C=180\°$

On putting the values, we get;

$\angle 1+115\°=180\°\\\\\angle1=180\[tex]\therefore m\angle2=65\°$ -115\°=65\°[/tex]

Thus the measure of ∠1 is 65°.

For ∠2.

Since the given triangle is an isosceles triangle.

So, $m\angle1=m\angle2$

Thus the measure of ∠2 is 65°.

For ∠3.

Here ∠1, ∠2 and ∠3 are the three angles of the triangle.

So we use the angle sum property of triangle, which states that;

"The sum of all the angles of a triangle is equal to 180°".

$\therefore \angle1+\angle2+\angle3=180\°$

Now we put the values and get;

$65\°+65\°+\angle3=180\°\\\\130\°+\angle3=180\°\\\\\angle3=180\°-130\°=50\°$

Thus the measure of ∠3 is 50°.

For ∠4.

∠4 and ∠2 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle2 +\angle 4 =180\°$

Substituting the values of of angle 2 to find angle 4 we get;

$65\°+ \angle 4 = 180\°\\\\ \angle 4 = 180\°-65\°\\\\\angle 4= 115\°$

Thus the measure of ∠4 is 115°.

For ∠5.

∠4 and ∠5 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle4 +\angle 5 =180\°$

Substituting the values of of angle 4 to find angle 5 we get;

$115\°+ \angle 5 = 180\°\\\\ \angle 5 = 180\°-115\°\\\\\angle 5= 65\°$

Thus the measure of ∠5 is 65°.

Hence:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

6 0

3 years ago