5.4p+13.1=−2.6p+3.5 p=?

Mathematics

1 answer:

mote1985 [20]3 years ago

7 0

Answer:

P= - 16/11 or P= - 1 5/11 or P= - 1.45455

Step-by-step explanation:

Just trust my answer

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blsea [12.9K]

Answer:

1 is biased, 2 isn't, 3 is biased, 4 isnt

Step-by-step explanation:

If you ask a question to people in a group who are already clearly for a certain topic then it is biased. For survey to not be biased, the people need to be chosen at random. Ask students what their favorite class is, or ask flight attendants where their favorite destination to travel to is. Dont use a group who has any relation to the survey at hand. Asking band students about funding for band is biased, as well as asking people who are at a SOCCER GAME what their favorite sport is.

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3 years ago

For the function f(x) = -2(x + 3)^2 -1, identify the vertex, domain, and range. A.) The vertex is (3, -1), the domain is all rea

Vlada [557]

Ok so domain is all allowed numbers look at deonomenator and don't allow any numbers that will make it zero none that means domain=all real numbers vertex in form y=a(x-h)^2+k (h,k)=vertex we have y=-2(x+3)^2-1 h=-3 k=-1 vertex=(-3,-1) range the vertex opens down so max is y=-1 y≤-1 domain is all real vertex is (-3,-1) y≤-1 C

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3 years ago

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g. How many of each weight is needed?

Delicious77 [7]

The required number of weights used in chemical balance to weigh 237g is 4,1,1,7 respectively.

What is mathematical expression?

A mathematical expression expression in mathematical is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Here, it is given that :

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g.

Now, let us find the number of weights for each weight type :

For 50g weight the maximum number of weights needed will be 4 that is :

50g x 4 = 200g

Now, for 20g weight the maximum number of weights needed will be 1 that is :

20g x 1 = 20g

Now, for 10g weight the maximum number of weights needed will be 1 that is :

10g x 1 = 10g

Now, for 1g weight the maximum number of weights needed will be 7 that is :

1g x 7 = 7g

Adding all the weights we get :

200g + 20g + 10g + 7g = 237g;

which is the required weight and the number of weights used is 4,1,1,7 respectively.