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ExtremeBDS [4]
3 years ago
7

5.4p+13.1=−2.6p+3.5 p=?

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0

Answer:

P= - 16/11 or P= - 1 5/11 or P= - 1.45455

Step-by-step explanation:

Just trust my answer

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If R is (-4,7) and S is (-2, 12), what is the component form of the vector RS?
serg [7]

Answer: (-6,19)

Step-by-step explanation:

Add -4 and -2

then add both y1 and y2

5 0
3 years ago
Can ya'll do my math homework too pleaseee? again I'll give brainliest and be rlly happy.
RUDIKE [14]

Answer:

1. f = -9

2. x = -7

3. x = -9

4. x = -20

5. y = 7.5

Step-by-step explanation:

Hope this helps

5 0
3 years ago
Read 2 more answers
3.<br>June has 248 oranges. She sells of these oranges. How many oranges did June sell?<br>Answer.​
uranmaximum [27]

Answer:

93. Divide 248 by 8. One eighth of 248 = 31.

June sold 3/8 of the 248 oranges.

If 1/8 = 31 and June sold 3/8 of the oranges.

Multiply 3 × 31. Therefore June sold 93 oranges.

Step-by-step explanation:

5 0
3 years ago
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Maria solved the equation below and got x = –4. Which of the following choices verifies that her solution is correct? 5x + 22 =
VladimirAG [237]
5(-4)+22 = (-4)+6
-20+22 = -4+6
2 = 2
Maria is correct, since both sides equally match.
3 0
3 years ago
Read 2 more answers
In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
4 years ago
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