We know that
speed=distance/time
solve for time
time=distance/speed
in this problem
<span>Marco runs at a rate of 6 miles per hour.
</span><span>Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
speed=1.2 miles/hour
distance=0.3 miles
time=?
</span>time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes
<span>
the answer is
0.25 hour (15 minutes)
Alternative Method
Let
x---------> Fernando's distance when Marco is 0.3 miles apart
</span>Fernando funs at a rate of 7.2 miles per hour
<span>for distance =x
time=x/7.2------> equation 1
</span>Marco runs at a rate of 6 miles per hour.
for distance=x-0.30
time=(x-0.30)/6------> equation 2
equate equation 1 and equation 2
7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles
time=x/7.2-----1.8/7.2=0.25 hour
Answer:
Sydney is 44 years old
Step-by-step explanation:
<u>Step 1: Make a system of equations
</u>
d = s - 15
<em>d + s = 73
</em>
<u>Step 2: Plug in s - 15 for d in the second equation and solve
</u>
s - 15 + s = 73
2s - 15 = 73 + 15
2s / 2= 88 / 2
<em>s = 44
</em>
Answer: Sydney is 44 years old
An equivalent fraction for 1/2 would be 2/4. This is because you can simplify 2/4 by dividing it by 2. The final answer would be 1/2.
An equivalent fraction for 4/5 would be 8/10. It's basically the same thing. Divide them both by 2 and you'll get 4/5 since 8 divided by 2 is 4, and 10 divided by 2 is 5.
Answer:
On which topic is he making?
Answer:
11 in
Step-by-step explanation:
Area of a square is L^2
where L is length.
L^2 = 121 in^2
FIND THE SQUARE ROOT OF BOTH SIDES (including in^2).
L= 11 in.
side = 11 in
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