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makvit [3.9K]
3 years ago
9

Given pq || bc. Find the length of aq

Mathematics
1 answer:
ki77a [65]3 years ago
5 0
Am bc it is a example as a gh
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If tan(A+B)=8 and tan B = 1/57 find tan A <br> Plz show work
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Step-by-step explanation:

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Covert 13/2 to a decimal using long division
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The Rodriguez family went to dinner at Pasta Palace. Mr. Rodriguez ordered a meal for $6.25; Mrs. R ordered a meal for $7.50; th
Romashka-Z-Leto [24]
Given:
Mr. Rodriguez :                          6.25
Mrs. R                                        7.50
2 children @ 4.99 each       <u>      9.98</u>
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Sales tax 7.25%                        1.72        *23.73 x 7.25%
Total tip 15%                         <u>    3.56  </u>      *23.73 x 15%
Grand total                            $29.01


Tips should be applied to pre-tax amount not post-tax. However, some companies compute tip based on post-tax amount. This means that the tip you are paying is computed based on the total amount of the meal as well as the sales tax you paid for the meal.

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Jonathan purchased 30 markers for $5.40. What is the price per marker?
madreJ [45]

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Step-by-step explanation:

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Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
3 years ago
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