Answer:
A=34, G=31
Step-by-step explanation:
G=A-3
2G+A=99
plug in for g 2(A-3)+A=99
distribute 2 A-3+A=99
combine like terms 3A-3=99
solve for a 3A=102 A=34
plug in a solve for g G=34-3 G=31
Answer:
The answers to the first question are A,C,D
The answer to the second question is YZ=16
Step-by-step explanation:
(1st Question)
Since <K and <M Are equal, and both <L's are equal, KL and ML are congruent (Answer choice) because of the ASA postulate.
You need to create the following equation to find the length of KN and MN 7x-4=5x+12
(Get the "x" variable to one side)
2x-4=12
(Isolate the variable)(Remove the 4)
2x=16
(Divide the 2 by itself to remove it from the x, remember to divide both sides by 2)
x=8 (Answer Choice)
Plug in the x value into each equation
KN= 7(8)-4
KN= 56-4
KN= 52
MN= 5(8)+12
MN= 40+12
MN= 52 (Answer Choice)
MN=KN
(Second Question)
Since XWY(20) is half of XWZ(40), ZWY also equals 20.
This now proves the triangle is congruent by the AAS postulate.
Since the triangles are congruent, if XY = 16, YZ also equals 16.
C because if the denominator equals x-2 that means that the horizontal asymptote happens at x=2. And because the numerator and denominator have the same degree then you divide leading coefficients to get the vertical asymptote at y=-2
