For a linear function, the instantaneous rate of change is everywhere equal to the slope. Thus the rate of change of the function h(x)=2x on the interval 2≤x≤4
The rate of change of the function given will equal to its slope, thus;
slope,m=(y-1-y)/(x_1-x)
=(2*4-2*2)/(4-2)
=(8-4)/2
=4/2
=2
the answer is 2
Given the equation - x² + 5x = 3, which can be rewritten as:
- x² + 5x - 3 = 0
where a = -1, b = 5 and c = -3.
Quadratic formula:
![\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2\text{ - 4ac}}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Csqrt%5B%5D%7Bb%5E2%5Ctext%7B%20-%204ac%7D%7D%7D%7B2a%7D)
Now, we just replace the values of a, b and c on the equation above.
![\frac{-5\text{ }\pm\text{ }\sqrt[]{5^2\text{ - 4(-1)(3)}}}{2(-1)}](https://tex.z-dn.net/?f=%5Cfrac%7B-5%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B5%5E2%5Ctext%7B%20-%204%28-1%29%283%29%7D%7D%7D%7B2%28-1%29%7D)
=
![\frac{5}{2}\text{ }\pm\text{ }\frac{\sqrt[]{13}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Cfrac%7B%5Csqrt%5B%5D%7B13%7D%7D%7B2%7D)
Sam is using an industrial kitchen to make several batches of his famous chocolate chip granola bars. He needs to weight out 78 ounces of chocolate chips, plus or minus 2.5 ounces. The equation that can be used to find the minimum or maximum amount,c, of chocolate chips that he can weigh out is-
Absolute value equation is = |c-2.5| = 78
The number of cats that you have is; 27 cats
<h3>How to calculate algebra word problems?</h3>
Let the number of cats alice has be x.
Since you have thrice the amount of cats that alice has, then you have 3x cats.
Bob has 7 less cats than you. Thus, bob has; 3x - 7
If they have a total of 56 cats, then;
x + 3x - 7 + 3x = 56
7x - 7 = 56
7x = 56 + 7
7x = 63
x = 63/7
x = 9
Thus, number of cats you have = 3x = 3 * 9 = 27 cats
Read more on algebra word problems at; brainly.com/question/13818690
First problem:
The answer is C because theoretically it should have a 50% of landing
heads but instead it lands heads 56% of the time. Thus this is 6% higher
than 50%. It's not D because there is not specified detail of how the
person got this data so you can assume that the person did a fair
survey/data collection.
Second problem:
So in a data size of 490, 140 of them we trout. This means that 140/490 or 28.57% of the fish are trout. This means that in a sample size of 5000 fish, 5000*0.2857 or 1428.57 are trout.
Third problem:
The Science students seem to have a higher average score because the average score of Math students are:
(32+33+34+34+35+37+39+40+40)/9=36
average score of Science students are:
(41+42+43+43+46+46+47+49+49)/9=45.111
