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3 years ago

1. Which of the following process is /are evaporation process

1 answer:

4 0

Evaporation process is by which water changes to gas or vapor.
The primary pathway that water moves from liquid state back into the water cycle as atmospheric water vapor.

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As a football player moves in a straight line [displacement (3.00 mm)i^i^ - (6.50 mm)j^j^], an opponent exerts a constant force

Brilliant_brown [7]

Answer:

Work done, $W=(0.378i-1.092j)\ J$

Explanation:

Displacement,

$d=(3i-6.5j)\ mm\\\\d=(0.003i-0.0065j)\ m$

Force, $F=(126i+168j)\ N$

Work done by the opponent do on the football player is given by :

$W=F{\cdot} d\\\\W=(126i+168j){\cdot} (0.003i-0.0065j)\ m\\\\W=(0.378i-1.092j)\ J$

So, the work done by the opponent do on the football player is $(0.378i-1.092j)\ J$ .

4 0

3 years ago

Read 2 more answers

A 4.4 kg marble (really big heavy marble) is accelerating down an incline. When it reaches level ground it slows down to a stop

KengaRu [80]

Mass=4.4kg

acceleration=-1.74m/s^2

Use newtons second law

$\\ \rm\longmapsto Force=ma$

$\\ \rm\longmapsto Force=4.4(-1.74)$

$\\ \rm\longmapsto Force=-7.656N$

initial velocity=u

Final velocity=v=0

Acceleration=a=-1.74m/s^2

Time=t=1.27s

$\\ \rm\longmapsto a=\dfrac{v-u}{t}$

$\\ \rm\longmapsto u=v-at$

$\\ \rm\longmapsto u=0-(-1.74)(1.27)$

$\\ \rm\longmapsto u=1.74(1.27)$

$\\ \rm\longmapsto u=2.2m/s$

4 0

3 years ago

Imagine whirling a ball on a string over you head. Suppose the knot holding the ball comes loose and the ball is instantly relea

zaharov [31]

B is the answer to the question

8 0

3 years ago

A 1.2kg stone is tied to a string and swung in a vertical circle with a radius of 0.75m. The string can withstand a tension of 4

san4es73 [151]

Hello!

We can begin by summing the forces acting on the stone when it is at the bottom of its trajectory.

Refer to the free-body diagram in the image below for clarification.

We have the force of tension (produced by the string) and the force of gravity acting in opposite directions, so:
$\Sigma F = T - F_g$

The net force is equivalent to the centripetal force experienced by the stone. Recall the equation for centripetal force for uniform circular motion:
$F_c = \frac{mv^2}{r}$

m = mass of object (1.2 kg)
v = velocity of object (? m/s)
r = radius of circle (0.75 m)

The centripetal force is the resultant of the forces of tension and gravity, and points upward (same direction as the tension force) since the tension force is greater.

Therefore:
$\frac{mv^2}{r} = T - Mg$