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il63 [147K]
4 years ago
10

Jenny wants to determine if a new brand name washing detergent is better than her old detergent she washed ten dirty t-shirts wi

th the new washing detergent and ten dirty t-shirts with the old detergent identify the dependent and independent variables for this experiment
Physics
1 answer:
katovenus [111]4 years ago
4 0

Answer:


Independent variable: washer detergent

Dependent varaible: cleaing power of effectivenes of the detergent.


Explanation:


When an experiiment is performed there exists one independent variable, one dependent variable, and some other variables that must be controlled.


The goal of the experiment is to test a hypothesis, which is a statement that relates an effect with a cause and that must be proved true or false.


The effect in the dependent variable, and the cause is the independent variable.


Jenny (the scientist) wants to show how an effect or phenomenun, the dependent variable, is explained by the explanatory, independent, variable.


In the stated experiment, Jenny wants to know how the effectiveness of a new brand detergent and an old one compare with each other. Therefore, she designs a test in which she will determine how the brand of detergent may  explain (explanatory or independent variable) the cleaning power or effectiveness, the dependent variable.


Jenny only can manipulate the independent variable and observe the effect on the dependent variable.


To be conclusive, other variables must be controlled, like the fabric and the amount of dirt of the t-shirts.

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Given :

Number of operations move through a pocket calculator during a full day's operation , n=1.34 \times 10^{20} .

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How many coulombs of charge moved through it .

Solution :

We know , charge in  one electron is :

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A recent home energy bill indicates that a household used 475475 kWh (kilowatt‑hour) of electrical energy and 135135 therms for
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Answer:

Explanation:

Given that,.

A house hold power consumption is

475 KWh

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Given that, 1 thermal = 29.3 KWh

Then,

135 thermal = 135 × 29.3 = 3955.5 KWh

So, total power used is

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P =4430.5 KWh

Since 1 hr = 3600 seconds

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P = energy / time

Energy = Power × time

E = 4430.5 KWhr × 1000W / KW × 3600s / hr

E = 1.595 × 10^10 J

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m = 1.595 × 10^10 / (3 × 10^8)²

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Then,

1 kg = 10^6 mg

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