Answer:
Larger tubines generate more electricity.
Explanation:
Larger blades allow the turbine to capture more of the kinetic energy of the wind by moving more air through the rotors. However, larger blades require more space and higher wind speeds to operate. This distance is necessary to avoid interference between turbines, which decreases the power output.
1.) The properties of a wave are the following.
a) <span><span>Amplitude - the height of the wave, measured in meters.
</span><span>b) Wavelength - the distance between adjacent crests, measured in meters.
</span><span>c) Period - the time it takes for one complete wave to pass a given point, measured in seconds.
</span><span>d) Frequency - the number of complete waves that pass a point in one second, measured in inverse seconds, or Hertz (Hz).
</span><span>e) Speed - the horizontal speed of a point on a wave as it propagates, measured in meters / second.
Among these properties, PERIOD and SPEED changes if the wave changes media. The others remain the same.
2. Speed = Wavelength * Frequency
Wavelength and Frequency are independent from each other. But you can use the given formula and assume values to check the reaction of one from another.
3. Energy of a wave is based on its amplitude. High amplitude means high energy and vice versa. To increase the energy of a wave, the amplitude must be increased. Another way of increasing the energy of a wave is using elastic medium. </span></span>
D, because the hairdryer uses a fan
E, because it produces heat
Hermes has a rotating wheel, or centrifuge, to provide artificial gravity for the crew. Spaceships in “2001: A Space Odyssey” and “Mission to Mars” were similarly equipped. Although it is not shown in the film, the astronauts would have used a Mars descent vehicle (MDV) to get down from Hermes to the surface.
Answer:
(2)


Explanation:
<u>a)Kinematics equation for the first ball:</u>


initial position is the building height
The ball reaches the ground, y=0, at t=t1:

(1)
Kinematics equation for the second ball:


initial position is the building height
the ball is dropped
The ball reaches the ground, y=0, at t=t2:

(2)
the second ball is dropped a time of 1.03s later than the first ball:
t2=t1-1.03 (3)
We solve the equations (1) (2) (3):






vo=8.9m/s

t2=t1-1.03 (3)
t2=3.29sg
(2)
b)
t1 must : t1>1.03 and t1>0
limit case: t1>1.03:





limit case: t1>0:



