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3 years ago

Solve for x 3x(3+5x)=240

Mathematics

1 answer:

AleksandrR [38]3 years ago

8 0

Answer:

x = 10

Step-by-step explanation:

3 $3x(3+5x)=240\\9x+15x^{2} =240\\\\9x+\sqrt{15x^{2} } =240\\9x+15x=240\\24x=240\\x=10$

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The sum of two negative integers is a negative integers

Vaselesa [24]

Answer:

when we add two negative numbers the result will always be a negative number, on adding negative numbers the direction of the move will always be to the left side

hope this helps!

3 0

2 years ago

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AVprozaik [17]

Idk what that answer is but good luck

4 0

3 years ago

Someone help me asap math 10

Ghella [55]

Answer:

x ≈ 25.4 Km

Step-by-step explanation:

Using the tangent ratio in the right triangle on the right

tan54° = $\frac{opposite}{adjacent}$ = $\frac{opp}{17}$ ( multiply both sides by 17 )

17 × tan54° = opp , thus

opp ≈ 23.4

-------------------------------------------

Using the cosine ratio in the right triangle on the left

cos23° = $\frac{adjacent}{hypotenuse}$ = $\frac{23.4}{x}$ ( multiply both sides by x )

x × cos23° = 23.4 ( divide both sides by cos23° )

x = $\frac{23.4}{cos23}$ ≈ 25. 4 Km ( to the nearest tenth )

6 0

3 years ago

Tim is training for a marathon, He ran 24 miles in 5 days, if he ran the same distance each diay, how far did he run per day?

malfutka [58]

Answer:

I believe its 4.8, which is confusing seeing as its not an option.

Step-by-step explanation:

If he ran 24 miles in 5 days, divide 24 by 5 to get your answer.

7 0

3 years ago

What are the coordinates of the point LaTeX: \frac{3}{4}\:3 4of the way from A to B? coordinate plane with line segment AB. Poin

egoroff_w [7]

Answer: $\left(\dfrac{-7}{2},\dfrac{5}{4}\right)$ .

Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

We need to find the coordinates of the point which is 3/4 of the way from A to B.

Let the required point be P.

$AP:AB=3:4$

$AP:PB=AP:(AB-AP)=3:(4-1)=3:1$

It means, point P divides segment AB in 3:1.

Section formula: If a point divides a line segment in m:n, then

$\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)$

Using section formula, we get

$P=\left(\dfrac{3(-3)+1(-5)}{3+1},\dfrac{3(3)+1(-4)}{3+1}\right)$

$P=\left(\dfrac{-9-5}{4},\dfrac{9-4}{4}\right)$

$P=\left(\dfrac{-14}{4},\dfrac{5}{4}\right)$

$P=\left(\dfrac{-7}{2},\dfrac{5}{4}\right)$

Therefore, the required point is $\left(\dfrac{-7}{2},\dfrac{5}{4}\right)$ .

6 0

3 years ago