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ra1l [238]
2 years ago
9

The radioactive element​ carbon-14 has a​ half-life of 5750 years. A scientist determined that the bones from a mastodon had los

t 57.5​% of their​ carbon-14. How old were the bones at the time they were​ discovered?
Mathematics
1 answer:
Arisa [49]2 years ago
8 0

Therefore, the bones were 6612.5 years old at the time they were discovered.

<h3><u>Half life</u></h3>

Given that the radioactive element​ carbon-14 has a​ half-life of 5750 years, and a scientist determined that the bones from a mastodon had lost 57.5​% of their​ carbon-14, to determine how old were the bones at the time they were discovered, the following calculation must be made:

  • 50 = 5750
  • 100 = 11500
  • 57.5 = X
  • 57.5 x 11500 / 100 = X
  • 6612.5 = X

Therefore, the bones were 6612.5 years old at the time they were discovered.

Learn more about half life in brainly.com/question/24710827

#SPJ1

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Wolfrich lived in Portugal and Brazil for a total period of 14 months in order to learn Portuguese. He learned an average of 130
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3 years ago
The city of Orlando’s building a dog park in downtown Orlando dog park will be triangular shaped as shown on the coordinate plan
kiruha [24]

Answer:

Perimeter of the dog park = 15.4 yards

Step-by-step explanation:

Coordinates of the vertices of the given triangle are,

P(1, 2), Q(1, 6), R(-4, 2)

Since distance between the two points (x_1, y_1) and (x_2,y_2) is,

d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Length of PQ = \sqrt{(1-1)^2+(2-6)^2}

PQ = 4

Length of PR = \sqrt{(1+4)^2+(2-2)^2}

PR = 5

Length of QR = \sqrt{(1+4)^2+(6-2)^2}

QR = \sqrt{25+16}

     = \sqrt{41}

     = 6.4 yards

Therefore, perimeter of the given triangle = PQ + QR + PR

                                                                       = 4 + 6.4 + 5

                                                                       = 15.4 yards

4 0
4 years ago
SOMEONE PLZZZ ANSWER THIS IM VERY BAD AT THIS!!
Furkat [3]

Answer:

Step-by-step explanation:

A. Linear- the add up to 180

B. 3x-5+2x+3+4x+2=180

   9x=180

    x=20

C. plug x in

   ABD- 55, DBK- 82, KBC- 43

7 0
3 years ago
Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x
Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0
3 years ago
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