Y-coordinates are same so you just need to find distance from -4 to -8 which would be 4 because |-4 - -8| = |-4 + 8| = 4.
Final answer: 4
Hope this helps.
Answer:
Hope this helps sorry I'm in class right now
Step-by-step explanation:
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
{ 3-y=2x
{ x+1/2y=3/2
{ -y=2x-3
{ 1/2y=3/2-x
{ y=-2x+3
{ y=3-2x
-2x+3=3-2x
(x,y) = (x,-2x+3)
Solution:
1) Simplify \frac{1}{6}x to \frac{x}{6}
y=\frac{x}{6}-2
2) Add 2 to both sides
y+2=\frac{x}{6}
3) Multiply both sides by 6
(y+2)\times 6=x
4) Regroup terms
6(y+2)=x
5) Switch sides
x=6(y+2)
Done!