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3 years ago

Please Help!!! And explain!!! Solve for x 7(5x-4)-1=14-8x

1 answer:

5 0

Hello there,
begin by distributing 7
35x-28-1=14-8x
35x-29=14-8x
now add 8x to both sides
35x+8x-29=14-8x+8x
43x-29=14
add 29 to both sides
43x-29+29=14+29
43x=43
divide both sides by 43
43x/43=43/43
x=1
Done!

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Dayami works at Future Shop and earns $10.50/h plus 6% commission on sales. Last

skad [1K]

<h2><u>Quick answer</u> :</h2>

$= \tt\$570$

<h2><u>Answer with steps</u> :</h2>

Money Dayami earns for an hour's work = $10.50

Number of hours Dayami worked last week = 40

Money Dayami would have gotten for her work :

$=\tt 10.50 \times 40$

$=\tt \$ \: 420$

Thus, money earned by Dayami for her work = $420

Total sales Dayami made last week = $2050

Money Dayami must have earned as commission :

= 6% of total sales

$= \tt6 \% \: of \: 2500$

$= \tt\frac{6}{100} \times 2500$

$=\tt \frac{15000}{100}$

$=\tt \$150$

Thus, money Dayami earned as a commission = $150

Dayami's weekly gross salary last week :

$= \tt420 + 150$

$=\color{plum} \tt \: \$570$

Thus, total salary = $570

Therefore, Dayami's gross salary last week =<u> $570</u>

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3 years ago

Which property justifies the following statement? If 12x = 84, then x = 7

makkiz [27]

Answer:

<h2>B. Division Property of Equality </h2>

Step-by-step explanation:

$12x=84\qquad\text{divide both sides by 12}\\\\\dfrac{12x}{12}=\dfrac{84}{12}\\\\x=7$

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3 years ago

3x-1/5-2/9x=124/5<br>how do you solve this?

Sergeu [11.5K]

So first you would combine the like-terms so you get:
$\frac{7}{9} x - \frac{1}{5} = 124 \div 5$
and combine the second like-terms:
$\frac{7}{9}x - \frac{1}{5} = 24.8$
now you only have a two step equation and you continue by doing the reciprocal and you add the -1/5 to the 24.8 where you get:

7/9x=24.6

then because the 7/9 is being multiplied by the x and your trying to isolate it you divide it by the 7/9 on both sides and you'll end up getting

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4 years ago

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choli [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1200\\
r=rate\to 6.5\%\to \frac{6.5}{100}\to &0.065\\
n=
\begin{array}{llll}
\textit{times it compounds per year}
\end{array}\to &4\\
t=years\to &6
\end{cases}
\\\\\\
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