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Feliz [49]
3 years ago
5

Evaluate ( 4 upon 3 ) -2please amswer fast​

Mathematics
1 answer:
Taya2010 [7]3 years ago
6 0
<h2><u>Solution</u></h2>

\frac{4}{3}  - 2 \\  \\   = \frac{4 - 6}{ 3}  \\  \\  =  \frac{ - 2}{3}

<h3>Hope This Helps You ❤️</h3>
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HELP!! let f be defined as shown. what is f^-1(-3)?
Assoli18 [71]

Answer:

F is the base or variable.

if it is asking for a simplifed version of this its -3/f

Step-by-step explanation:

3 0
2 years ago
PLEASE HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!
disa [49]

Answer:

C. 15 votes

Step-by-step explanation:

B= votes Billy got

K = votes Keeton got

B = 3K


B+K =20

Substitute the first equation into the second equation

3K + K =20

Combine like terms

4K =20

Divide both sides by 4

4K/4 = 20/4

K =5

Keeton got 5 votes

B = 3*K

B = 3*5

B = 15 votes

Billy got 15 votes

3 0
3 years ago
A pumpkin is thrown horizontally off of a building at a speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2, point, 5, start fract
4vir4ik [10]

Answer:−47.0

​

​

Step-by-step explanation:Step 1. List horizontal (xxx) and vertical (yyy) variables

xxx-direction yyy-direction

t=\text?t=?t, equals, start text, question mark, end text t=\text?t=?t, equals, start text, question mark, end text

a_x=0a

x

​

=0a, start subscript, x, end subscript, equals, 0 a_y=-9.8\,\dfrac{\text m}{\text s^2}a

y

​

=−9.8

s

2

m

​

a, start subscript, y, end subscript, equals, minus, 9, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction

\Delta x=12\,\text mΔx=12mdelta, x, equals, 12, start text, m, end text \Delta y=\text ?Δy=?delta, y, equals, start text, question mark, end text

v_x=v_{0x}v

x

​

=v

0x

​

v, start subscript, x, end subscript, equals, v, start subscript, 0, x, end subscript v_y=\text ?v

y

​

=?v, start subscript, y, end subscript, equals, start text, question mark, end text

v_{0x}=2.5\,\dfrac{\text m}{\text s}v

0x

​

=2.5

s

m

​

v, start subscript, 0, x, end subscript, equals, 2, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction v_{0y}=0v

0y

​

=0v, start subscript, 0, y, end subscript, equals, 0

Note that there is no horizontal acceleration, and the time is the same for the xxx- and yyy-directions.

Also, the pumpkin has no initial vertical velocity.

Our yyy-direction variable list has too many unknowns to solve for v_yv

y

​

v, start subscript, y, end subscript directly. Since both the yyy and xxx directions have the same time ttt and horizontal acceleration is zero, we can solve for ttt from the xxx-direction motion by using equation:

\Delta x=v_xtΔx=v

x

​

tdelta, x, equals, v, start subscript, x, end subscript, t

Once we know ttt, we can solve for v_yv

y

​

v, start subscript, y, end subscript using the kinematic equation that does not include the unknown variable \Delta yΔydelta, y:

v_y=v_{0y}+a_ytv

y

​

=v

0y

​

+a

y

​

tv, start subscript, y, end subscript, equals, v, start subscript, 0, y, end subscript, plus, a, start subscript, y, end subscript, t

Hint #22 / 4

Step 2. Find ttt from horizontal variables

\begin{aligned}\Delta x&=v_{0x}t \\\\ t&=\dfrac{\Delta x}{v_{0x}} \\\\ &=\dfrac{12\,\text m}{2.5\,\dfrac{\text m}{\text s}} \\\\ &=4.8\,\text s \end{aligned}

Δx

t

​

 

=v

0x

​

t

=

v

0x

​

Δx

​

=

2.5

s

m

​

12m

​

=4.8s

​

Hint #33 / 4

Step 3. Find v_yv

y

​

v, start subscript, y, end subscript using ttt

Using ttt to solve for v_yv

y

​

v, start subscript, y, end subscript gives:

\begin{aligned}v_y&=v_{0y}+a_yt \\\\ &=\cancel{0\,\dfrac{\text m}{\text s}}+\left(-9.8\,\dfrac{\text m}{\text s}\right)(4.8\,\text s) \\\\ &=-47.0\,\dfrac{\text m}{\text s} \end{aligned}

v

y

​

​

 

=v

0y

​

+a

y

​

t

=

0

s

m

​

​

+(−9.8

s

m​

)(4.8s)

=−47.0

s

m

5 0
3 years ago
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