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galina1969 [7]
3 years ago
13

Mike has a credit rating of 720. Tyler has a credit rating of 560. Mike and Tyler apply for identical loans from Park Bank. Mike

is approved for a loan at 3.2% interest, and Tyler is approved for a loan that charged 3 percentage points higher because of his inferior credit rating. What interest rate is Tyler charged?
Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0

Answer: 45

Step-by-step explanation:

Eva8 [605]3 years ago
4 0

Answer:

6.2%

Step-by-step explanation:

Credit rating is an evaluation of the credit risk of a borrower, that how often a person is going to repay their debt, by credit rating it predicts the ability of the debtor to payback.

Mike has credit rating = 720

Tyler has credit rating = 560

Both are approved for loan. Mike's Credit score is higher, which means he is a much safer debtor as compared to Tyler. Mike will be able to pay back much easily than Tyler. Therefore Mike interest rate is 3.2%

Interest rate of Tyler is higher as he is not that trusted and has low Credit rating. Tyler is approved for a loan that charged 3 percentage points higher because of his inferior credit rating so it interest on the loan will be

Interest = 3.2%+3% = 6.2%

   

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Answer:

your answer would be A.

Step-by-step explanation:

Already you know that answers b and d are not an option because it is saying she can use OVER 45 dollars. So she has to use EQUAL or less then 45 dollars. So the answer has to be A or C. In answer C it is saying she can spend MORE then 2.50 for a bunch where she cant. She has to spend exactly or less then that amount. So your answer is A.

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A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while
ki77a [65]

Answer:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=12 represent the population standard deviation

n represent the sample size  

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is \alpha=1-0.96 =0.04. And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got z_{\alpha/2}=2.054, replacing into formula (b) we got:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

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