All categories

3 years ago

I really need help on this!

Mathematics

1 answer:

ella [17]3 years ago

7 0

The answer is it multiply's by 4. 70 time 4 is 280. that times 4 is 1,120. That times 4 is 4,480. That times 4 is 17,920.I hope this helps ^^

You might be interested in

Emma enjoys flying kites. her red kite has a maximum altitude of 117.46 meters, and her black kite has a maximum altitude of 362

7nadin3 [17]

You have to convert 117.46 meters to feet. so you know that 0.3048 meters is 1 foot.

117.46 / 0.3048= 385.37feet red kite
now you can simply subtract
385.37-362.26=23.11ft
the answer is, the red kite has an altitude 23.11 feet higher then the black kite.

5 0

2 years ago

Ivan biked 1 2/3 hours on monday 2 1/3 hours on tuesday and 2 2/3 hours on wednesday how many hours ivan spent biking

Ket [755]

56 hr an 40 min because 34+21=55+1hr from 3half+3half=1hr and 10min+30min will be 40 min its 55hr 40min.

7 0

3 years ago

Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩

klemol [59]

$\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle$

$\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt$

$\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle$

$\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1$

$\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2$

$\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3$

With the initial condition $\mathbf r(0)=\langle4,6,3\rangle$ , we find

$\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9$

$\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6$

$\dfrac92\cdot0^2+C_3=3\implies C_3=3$

So the particular solution to the IVP is

$\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle$

4 0

3 years ago

3. What is the slope of the line passing through (15,-5) and (3, -8)?

Andrej [43]

M= -8 - -5/ 3 - 15= -8+5/3-15= -3/-12 = 3/12 = 1/4

The slope is 1/4.
The slope formula is m=y2-y1/x2-x1. I plugged in -8=y2, -5=y1, 3=x2, and 15=x1. Then I solved it.

6 0

3 years ago

Read 2 more answers

From the side of a hill wai-kin looks up at the top of a nearby vertical cliff at an angle of elevation of 36 degrees and looks

oksano4ka [1.4K]

Answer:

881.5 meters.

Step-by-step explanation:

The horizontal plane at the level of wai-kin's eyes divide the height of the cliff into two parts. Let the upper part be represented by x and the lower part be represented by y.

The height of the cliff = x + y

Applying the appropriate trigonometry functions.

To determine the value of x;

Tan θ = $\frac{opposite}{adjacent}$