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Leokris [45]
2 years ago
14

I rlly need this answer pls help

Mathematics
1 answer:
mina [271]2 years ago
6 0

Answer:

d

Step-by-step explanation:

155$ after 3 months means 45$ less. 45$ divided by 3 (the number of months) =15

that means she spends 15$ per month

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Simplify the expression. (rt)^12
ch4aika [34]

Answer: Your answer is r^12t^12

Step-by-step explanation: You use the distribution property.


8 0
3 years ago
What is the common ratio between successive terms in the sequence?<br> 27, 9, 9, 1,<br> 3,<br> of
grin007 [14]

Answer:

What is the common ratio between successive terms in the sequence?

27, 9, 9, 1,

3,

of

8 0
2 years ago
Need help.....................................
adoni [48]

Answer: w, 0

Step-by-step explanation:

you can see that G has the same distance from 0 as E does, so you can just take away the - sign. It hasn't left the line so its still 0.

8 0
3 years ago
–5(–11)=?????????? please help me and answer it
Alja [10]

Answer:

55

Step-by-step explanation:

-5 (- 11)

= 55

5 0
2 years ago
Read 2 more answers
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
3 years ago
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