The chemical formula for aluminum flouride is C). AlF3.
First we need to find the number of moles of both K and O reacted
K - 0.779 g / 39 g/mol
= 0.02 mol
the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g
O₂ moles = 0.638 g / 32 g/mol
= 0.02 mol
the number of both K and O₂ moles reacted are equal
therefore stoichiometry of K to O₂ reacted are 1:1
then the formula of potassium superoxide is KO₂
The Hydrogen ion concentration of a pH 3.8 solution would be higher than that of a solution with a pH of 6.2. This is because since the pH scale measures the concentration of Hydrogen ions. We know that a pH range of less than 7 is considered acidic and greater than 7 is basic. If a solution is more acidic it would possess more hydrogen ions than if it weren't. In this case a pH value of 3.8 is more acidic than pH 6.2.
Answer:
2.73%
Explanation:
Molarity of NaOH = 0.75 M
Density of solution = 1.1 g/mL
Mass percent of NaOH = ?
Solution:
Number of moles of NaOH = 0.75 mol from 0.75 mol/L
Mass of NaOH = number of moles × molar mass
Mass of NaOH = 0.75 mol × 40 g/mol
Mass of NaOH = 30 g
Mass of solution:
d = m/v
1.1 g/ mL = m/ 1000 mL
m = 1100 g
Percentage of NaOH:
% NaOH = mass of solute / mass of solution × 100
% NaOH = 30 g/ 1100 g × 100
% NaOH = 2.73%
Answer:
Explanation:
Okay I just took this test and I will just tell you now
D is not the answer.
Sorry I couldn't be more help
