All categories

3 years ago

Find the square root of 64a^2/9b^2+4+32a/3b

Mathematics

1 answer:

insens350 [35]3 years ago

8 0

Answer:

the square root of 64a^2/9b^2+4+32a/3b is

( 8a + 6b ) / 3b

8a / 3b + 2

You might be interested in

Is 20% greater than 0.02

Ket [755]

Yep it is greater. Hope this helps

6 0

3 years ago

51 more than y is greater than -240

svet-max [94.6K]

Answer:

y + 51 ≥ -240

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

3 years ago

(5x+3)(7x-7) how do find x

Delvig [45]

We can use the FOIL method to solve.

(5x + 3)(7x - 7)

(5x * 7x) + (5x * -7) + (3 * 7x) + (3 * -7)

35x - 35x + 21x - 21

0 + 0

Best of Luck!

6 0

3 years ago

-8(2b-7)-9(b-5)<br>simplify

GenaCL600 [577]

Answer:

Step-by-step explanation:

$-8(2b-7)-9(b-5)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(-8)(2b)+(-8)(-7)+(-9)(b)+(-9)(-5)\\\\=-16b+56-9b+45\qquad\text{combine like terms}\\\\=(-16b-9b)+(56+45)\\\\=-25b+101$

3 0

3 years ago

Read 2 more answers

Find the square root of 64a^2/9b^2+4+32a/3b​

Find the square root of 64a^2/9b^2+4+32a/3b