Answer:
Area of the sector = 57.26295cm²
Step-by-step explanation:
Radius of the circle=9cm
π= 3.142
Angle at B= 81° ( opposite angle of a quadrilateral)
Area of the sector = πr² * 81/360
Area of the sector = 3.142 * 9*9 * 0.225
Area of the sector= 3.142*81*0.225
Area of the sector = 57.26295cm²
Not sure at all but i think the 18 one
Answer:
The larger acute angle is equal to 50.8 degrees.
Step-by-step explanation:
Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.
A = cos^-1 (2√6/2√15)
However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,
A = cos^-1 (2√90/30) = 50.768 degrees.
B = sin^-1 (2√90/30) = 39.231 degrees.
Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.
cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.
If you have any questions on where I got a formula or any step, feel free to ask in the comments!
The top square is 8. The long rectangle 19.5. The bottom rectangle is 3.
