he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
Answer:
The equation would be x^2 + y^2 = 9
Step-by-step explanation:
In order to find this, start with the base form of the circle.
(x - h)^2 + (y - k)^2 = r^2
Now we input the center as (h, k).
(x - 0)^2 + (y - 0)^2 = r^2
x^2 + y^2 = r^2
Now we can input the radius of 3 in for r
x^2 + y^2 = 3^2
x^2 + y^2 = 9
Answer: y= -5/2x+3
Explanation: by converting the equation into slope-intercept form you can use the slope and y-intercept given in the equation to graph.
Step-by-step:
5x= -2y+6
2y= -5x+6
Y= -5/2x+3
Slope= -5/2x
Y-intercept= 3