80 is the estimate that I say it's pretty close
Answer:
#a. $80
#b. $1680
Step-by-step explanation:
We are given;
- Amount invested (principal) is $1600
- Rate of interest is 5%
- Time = 1 year
We are required to determine the amount of simple interest earned and the amount or balance in the account after 1 year.
#a. Interest earned
To calculate simple interest we use the formula;
I = (PRT) ÷ 100
Where, P is the principal, R is the rate, T is the time and I is the simple interest.
Therefore;
I = (1600 × 5 × 1) ÷ 100
= $80
Therefore, simple interest earned is $80
#b. Balance of the account (Amount accrued)
We are going to use the formula;
A = P + I , where A is the amount accrued, P is the principal and I is the simple interest earned.
Therefore;
Account balance = $1600 + $80
= $1680
Thus, the account balance after 1 year will be $1680
Answer:
-56
Step-by-step explanation:
Formula to get determinant is::
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
0(0)-8(7)
0 - 56
-56
Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
yes, you are correct. every input corresponds to only one output