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2 years ago

Solve the Inequality for x x/2+3/2<5/2

Mathematics

1 answer:

charle [14.2K]2 years ago

7 0

Answer:

x<2

Step-by-step explanation:

I didnt feel like typing it out but the explanation is in the picture hope this helps :)

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Ten and forty-one thousandths in expanded form and in standard

lyudmila [28]

10.041 is standard form and I don't know the expanded form

3 0

3 years ago

Help please!!!

katovenus [111]

Answer:

x = $\frac{7+\sqrt{47}\times i }{4}$

Step-by-step explanation:

<u>To solve quadratic systems,we always substitute one variable in terms if the other and then solve the equation.</u>

x + 2y = 6 ---------------(1)

y - 5 = $(x-2)^{2}$ ---------------(2)

y = $(x-2)^{2}$ + 5 ---------------(3)

Substitute (3) in (1) ,

x + 2( $(x-2)^{2}$ + 5 ) = 6

$(a + b)^{2}$ = $a^{2} + 2ab + b^{2}$

x + 2( $x^{2} - 4x + 4$ + 5 ) = 6

$2x^{2} - 7x + 12=0$ --------------(4)

The roots of the quadratic equation $ax^{2} +bx+c$ is

x = $\frac{(-b) + \sqrt{(-b)^{2}-4 \times ac } }{2 \times a}$ -----------(5)

According to equation (5),solution of (4) is

x = $\frac{7 + \sqrt{(-7)^{2}-4 \times 24 } }{2 \times 2}$

x = $\frac{7+\sqrt{49-96}}{4}$

x = $\frac{7+\sqrt{47}\times i }{4}$

4 0

3 years ago

In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet. Find the measure of ∠V to the nearest tenth of a degree.

Crazy boy [7]

Answer:

m<V = 11.2 degrees

Step-by-step explanation:

In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet.

From the triangle;

UV = hypotenuse = 6.2feet

WU = opposite = 1.2feet

Required

m<V

Using the SOH CAH TOA identity

sin m<V = opp/hyp

sin m<V = WU/UV

sin m<V = 1.2/6.2

sin m<V = 0.1936

m<V = arcsin(0.1936)

m<V = 11.16

m<V = 11.2 degrees ((to the nearest tenth of a degree)

4 0

2 years ago

Read 2 more answers

-3(12 - m) = -1(m - 8)

victus00 [196]

Answer:

m = 7

Step-by-step explanation:

- 3(12 - m) = - 1(m - 8)

- 36 - (- 3m) = - m - 8

- 36 + 3m = - m - 8

- 36 + 3m + m = - m + m - 8

- 36 + 4m = - 8

- 36 + 36 + 4m = - 8 + 36

4m = 28

4m ÷ 4 = 28 ÷ 4

m = 7

7 0

3 years ago

A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro

kati45 [8]

Answer:

$6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

Step-by-step explanation:

Probability that the car encounters a green light on the first day: $50 \% = 0.5$ .

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

$(0.5) \times 0.5 = 0.25$ .

Condition is met on the first two days and green light on the third day: $(0.5 \times 0.5) \times 0.5 = 0.125$ .
Condition is met on the first three days and green light on the fourth day: $(0.5 \times 0.5 \times 0.5) \times 0.5$ .

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be $(0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1$ .

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. $(0.5^{4} \times 0.1) \times 0.4$

Seventh day: $(0.5^{4} \times 0.1 \times 0.4 ) \times 0.4$
Eighth day: $(0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4$
Ninth day: $(0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4$
Tenth day: $(0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}$

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: $0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

6 0

3 years ago

Read 2 more answers