If one canadian dollar equals 0.802362 usd how much would 10 canadian dollars cost?
2 answers:
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Given:
The base is a rectangle of dimension 7 cm×6 cm.
The length of each diagonal side = 10 cm
To find the height of MT.
Formula
By Pythagoras theorem we get,
where, h be the hypotenuse
b be the base and
l be the height.
Now, in this diagram,
The perpendicular distance of M from BC = 3 cm
Slant height = 10 cm
Taking, b = 3 and h = 10 we get,
or,
or,
or,
Hence,
The height of MT is 9.5 cm.