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2 years ago

7

Please help!!! Will give brainly!! 50 points

1 answer:

lara31 [8.8K]2 years ago

5 0

$(x,\ y)\to(x-6,\ y-4)\\\\A(3,\ -5)\to A'(3-6,\ -5-4)\to A'(-3,\ -9)\\\\B(6,\ 2)\to B'(6-6,\ 2-4)\to B'(0,\ -2)\\\\C(2,\ 5)\to C'(2-6,\ 5-4)\to C'(-4,\ 1)$

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2 years ago

PLEASE HELP ILL GIVE BRAINLIEST

DanielleElmas [232]

Option A:

$(x-5)^{2}+(y-3)^{2}=16$

Solution:

Given data:

Center of the circle is (5, 3).

Radius of the circle = 4

To find the equation of the circle:

The general form of the equation of a circle in centre-radius format is

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where (h, k) is the centre of the circle and r is the radius of the circle.

Substitute the given values in the equation of a circle formula:

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$(x-5)^{2}+(y-3)^{2}=16$

The equation of the given circle is $(x-5)^{2}+(y-3)^{2}=16$ .

Hence Option A is the correct answer.

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