3 years ago

Please help!!! Will give brainly!! 50 points

1 answer:

5 0

$(x,\ y)\to(x-6,\ y-4)\\\\A(3,\ -5)\to A'(3-6,\ -5-4)\to A'(-3,\ -9)\\\\B(6,\ 2)\to B'(6-6,\ 2-4)\to B'(0,\ -2)\\\\C(2,\ 5)\to C'(2-6,\ 5-4)\to C'(-4,\ 1)$

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saveliy_v [14]

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ad-work [718]

Missing Question:

The question was missing information. I have found the question online and attaching it here for convenience.

Answer:

Option D

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Zinaida [17]

Answer:

C is the correct answe.

Step-by-step explanation:

$\frac{10 {y}^{7} - 8 {y}^{6} + 3 {y}^{4} } { {y}^{3} }$

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2 years ago

Read 2 more answers

Solve for v please? use additive property

Ahat [919]

V= -13
-7=v+6
-6 -6
-13=v

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