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frutty [35]
3 years ago
8

Gina made tables of values to solve a system of equations.

Mathematics
1 answer:
Jet001 [13]3 years ago
6 0
What’s the question
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When Harper commutes to work, the amount of time it takes her to arrive is normally distributed with a mean of 24 minutes and a
Korvikt [17]

Answer:

\mu -2\sigma = 24-2*3= 18

\mu -2\sigma = 24+2*3= 30

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

Step-by-step explanation:

For this case we can define the random variable X as the amount of time it takes her to arrive to work and we know that the distribution for X is given by:

X \sim N(\mu = 24, \sigma =3)

And we want to use the empirical rule to estimate the middle 95% of her commute times. And the empirical rule states that we have 68% of the values within one deviation from the mean, 95% of the values within two deviations from the mean and 99.7 % of the values within 3 deviations from the mean. And we can find the limits on this way:

\mu -2\sigma = 24-2*3= 18

\mu -2\sigma = 24+2*3= 30

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

7 0
3 years ago
How many whole sandwiches can be made with 3 pounds of turkey if each sandwich has 5 ounces of turkey on it? 4 6 9 10
Svetradugi [14.3K]
The answer is 9. there are 16 ounces in a pound so if you times that by three it is 48 ounces. 9 sandwiches equals 45 ounces
6 0
3 years ago
Read 2 more answers
Sue has taken four exams so far in her History course. Her scores are 84.0, 78.2, 93, and 87.5. What is the average of these sco
Nataliya [291]

Answer: 85.7

Step-by-step explanation:

3 0
3 years ago
For a school fundraiser students are selling snack bags and candy bars to raise money on Wednesday the students or 23 snack bags
meriva

Answer:

$1.75

Step-by-step explanation:

The selling for each candy bar may be determined by  a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation .

Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25

23s + 36c = 114.75

37s + 36c = 146.25

14s = 31.5

s = $2.25

23(2.25) + 36c = 114.75

36c = 114.75 - 51.75

36c = 63

c = 63/36

= $1.75

3 0
3 years ago
Consider the rational expression (IMAGE ATTACHED)
Keith_Richards [23]

Answer:

  • 3x² is a term in the numerator
  • x + 1 is a common factor
  • The denominator has 3 terms

Step-by-step explanation:

You can identify terms and count them before you start factoring. Doing so will identify 3x² as a term in the numerator, and will show you there are 3 terms in the denominator.

When you factor the expression, you get ...

  \dfrac{3x^2-3}{3x^2+2x-1}=\dfrac{3(x^2-1)}{(3x-1)(x+1)}=\dfrac{3(x-1)(x+1)}{(3x-1)(x+1)}

This reveals a common factor of x+1.

So, the above three observations are true of this rational expression.

3 0
3 years ago
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