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3 years ago

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50% of babies are born female.Olive wants to find the probability 20 or more of the 50 babies born today were female. If we use

a double-sided coin and assign heads as females and tails as males,what is the best way to perform this simiulation

1 answer:

Anna [14]3 years ago

3 0

Answer:

D. Keep track of the number of heads flipped in 50 flips. These represent the number of females born today. Repeat this 200 times.

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Write the equation of the line the passes through (1, -2) and (3, 4) in slope intercept form.

Alona [7]

Answer:

y=3x-5

Step-by-step explanation:

First find the slope, 4+2 over 3-1, giving you the slope of three

then set up your equation, y=3x+?

I played with the y=3x - part on the website desmos graphing calculator, I first inserted the points then found the slope and then played with the equation till it went through both the points.

4 0

3 years ago

A researcher collected data on the hours of TV watched per day from a sample of five people of different ages. Here are the resu

frozen [14]

Answer:

1. The least squares regression is y = -0.1015·x + 6.51

2. The independent variable is b) age

Please see attached table

Step-by-step explanation:

The least squares regression formula is given as follows;

$\dfrac{\sum_{i = 1}^{n}(x_{i} - \bar{x})\times \left (y_{i} - \bar{y} \right ) }{\sum_{i = 1}^{n}(x_{i} - \bar{x})^{2}}$

We have;

$\bar x$ = 24

$\bar y$ = 4

$\Sigma (x_i - \bar x) (y_i - \bar y)$ = -79

$\Sigma (x_i - \bar x)^2$ = 778

$\therefore \hat \beta =\dfrac{\sum_{i = 1}^{n}(x_{i} - \bar{x})\times \left (y_{i} - \bar{y} \right ) }{\sum_{i = 1}^{n}(x_{i} - \bar{x})^{2}} = \frac{-79}{778} = -0.1015$

The least squares regression is y = -0.1015·x + α

∴ α = y -0.1015·x = 6 - (-0.1015 × 5) = 6.51

The least squares regression is thus;

y = -0.1015·x + 6.51

2. The independent variable is the age b)

3. Steps to create an ANOVA table with α = 0.05

The overall mean = (43 + 30 + 22 + 20 + 5 + 1 + 6 + 4 + 3 + 6 )/10 = 14

There are 2 different treatment = $df_{treat} = 2 - 1 = 1$

There are 10 different treatment measurement = $df_{tot} = 10 - 1 = 9$

$df_{res} = 9 - 1 = 8$

$df_{treat} + df_{res} = df_{tot}$

The estimated effects are;

$\hat A_1 = 24 - 14 = 10$

$\hat A_2 = 4 - 14 = -10$

$SS_{treat} = 10^2 \times 5 + (-10)^2 \times 5 =1000$

$\sum_{i}\SS_{row}_i = \sum_{i}\sum_{j} (y_{ij} - \bar y)= [(1 - 4)^2 + (6 - 4)^2 + (4 - 4)^2 + (3 - 4)^2 + (6 - 4)^2] = 18$

$\sum_{i} S S_{row}_i = \sum_{i}\sum_{j} (y_{ij} - \bar y) ^2= [(43 - 24)^2 + (30 - 24)^2 + (22 - 24)^2 + (20 - 24)^2 + (5 - 24)^2] = 778$

$S S_{res} = \sum_{i} S S_{row}_i = 778 + 18 = 796$

$SS_{tot}$ = (43 - 14)² + (30 - 14)² + (22 - 14)² + (20 - 14)² + (5 - 14)² + (1 - 14)1² + (6 - 4 )² + (3 - 14)² + (6 - 14)² = 1796

$MS_{treat} = \dfrac{SS_{treat} }{df_{treat} } = \dfrac{1000}{1} = 1000$

$MS_{res} = \dfrac{SS_{res} }{df_{res} } = \dfrac{796}{8} = 99.5$

F- value is given by the relation;

$F = \dfrac{MS_{treat} }{MS_{res} } = \frac{1000}{99.5} = 10.05$

We then look for the critical values at degrees of freedom 1 and 8 at α = 0.05 on the F-distribution tables 5.3177

Hence; $F = 10.05 > F_{1,8}^{Krit}(5\%) = 5.3177$ , we reject the null hypothesis.

7 0

2 years ago

How do I solve -5x+2y=6

Olegator [25]

Answer: x = (2 y)/5 - 6/5 , y = (5 x)/2 + 3

Solve for x:
2 y - 5 x = 6
Subtract 2 y from both sides:
-5 x = 6 - 2 y
Divide both sides by -5:
Answer: x = (2 y)/5 - 6/5
Solve for y:
2 y - 5 x = 6
Add 5 x to both sides:
2 y = 5 x + 6
Divide both sides by 2:
Answer: y = (5 x)/2 + 3

4 0

2 years ago

What is the solution to this equation? X-14=-9

Reil [10]

5 - 14 = -9, therefore x = 5.

Hope this helps!

7 0

3 years ago

Read 2 more answers

The student council is ordering T-shirts from a website. The T-shirts cost $9 each and there is a shipping fee of $8 for any

Artist 52 [7]

Answer: They can order 78 shirts.

Step-by-step explanation:

9x + 8 = 710

9x = 702

x = 78

**Since the shipping fee is $8 for ANY amount ordered, the price of shipping doesn’t change with the number of shirts — the shipping price is a constant.

6 0

3 years ago