The Coefficients would be:
Hg(CO3)2: 1
AgCl: 4
HgCl4: 1
Ag2CO3: 2
How do we know this?
Because if we look at the coefficent for the first compound, Hg(CO3)2, That means in total we have one Hg and 2 CO3's.
IF the coefficient is 4 for the next compound, AgCl, there are 4 Ag's and 4 Cl's.
Those were the REACTANTS to our equation. Now looking at the arrow, HgCl4 and Ag2CO3 are our PRODUCTS, or, what is FORMED from Hg(CO3)2 and AgCl. So, we need to make sure that they are equal, to obey the law of conservation of mass. So in simpler terms, if we have 4 Cl's on the reactant side, we need 4 on the products side.
So, if we had the coefficient of 1 for HgCl4, this makes sense, because on the products side we had 1 Hg, and 4 Cl's. With the coefficient of 1, we have 1 Hg and 4 Cl's on the products side, as well!
And if we had the coefficient of 2 for Ag2CO3, we would have 4 Ag's total and 2 CO3s, which matches on the reactants side, for we have two CO3's and 4 Ag's.
I hope I could help!
<span>(a) Assuming the amount of O2(g) is not limiting the reaction, a mass of 4.23g of Ca(s) will produce an equal mass of CaO(s), hence it will produce 4.23g of CaO(s).
According to their respective molar masses, we have the following CaO molar mass :
Molar mass of Ca + Molar mass of O = 40.1 + 16 = 56.1 g/mol
4.23g of Ca will then produce : 4.23 / 56.1 = 0,07540107 mol of CaO.
(b) With the same reasonment as above, and assuming the amount of Ca is not limiting, we have :
2.87g of O2 will produce : 2.87 / 56.1 = 0,051158645 mol of CaO.
(c) From (a) and (b) answers, we can conclude that the reactant that produces less mol of CaO is limiting the reaction. Hence following the given masses, O2 is the limiting reactant.
(d) Knowing the molar mass of CaO is 56.1 g/mol and knowing that O2 is the limiting reactant, we also know the reaction can produce a maximum of 0,051158645 mol of CaO can be produced.
So we can conclude we will produce :
56.1 * 0,051158645 = 2.87g of CaO.</span>
Answer:
in crystalline solids
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The total ball pressure is sum of gauge pressure and atmospheric pressure
We know that atmospheric pressure = 101.325 kPa
so the total ball pressure = 61 kPa + 101.325 kPa = 162.325 kPa
Now we will use ideal gas equation as
PV = nRT
P = pressure = 162.325 kPa
V = 5.2 L
R = gas constant = 8.314 kPa L / mol K
T = 32 C = 273.15 + 32 = 305.15 K
n = moles = ?
Moles = PV / RT = 162.325 kPa X 5.2 / 305.15 X 8.314 = 0.332 moles