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vlada-n [284]
4 years ago
10

The disaccharide lactose can be decomposed into its constituent sugars galactose and glucose by acid hydrolysis or by the enzyme

lactase. Lactose intolerance in humans is due to the lack of lactase production by cells in the small intestine. However, the stomach is an acidic environment; therefore, one might expect lactose hydrolysis to still be an efficient process. The following data were obtained for the rate of lactose decomposition as a function of acid and lactose concentration. (14 pts)
Run [lactose]o (mol/L) [H+]o (mol/L) Initial rate (mol/L∙s)1 0.01 0.001 0.001162 0.02 0.001 0.002323 0.01 0.004 0.00464
a. Using this information, determine the rate law expression and the rate constant for the acid-based hydrolysis of lactose.
b. Based on your reaction order with respect to lactose only and using an initial concentration of 0.01 M lactose, determine what concentration of lactose would be after 10 minutes
Chemistry
1 answer:
Fed [463]3 years ago
6 0

Answer:

The answer is Disaccharide

Explanation:

Both Glucose and Galactose are a type of Monosaccharide. Because Lactose contains both Glucose and galactose, it contains 2 Monosaccharides, which make it Disaccharide

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The volume we need is 8.89 mL

Explanation:

We analyse data:

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pH can gives the information of protons concentrations, so as ratio is 1:1, 0.0199 M is also the molar concentration of HCl

Let's verify the molar concentration of the concentrated solution:

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As the solution mass is 100 g, we apply density to find out the volume:

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Let's convert the volume from mL to L in order to define molarity

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Let's apply the dilution formula:

M concentrated . V concentrated = M diluted . V diluted

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V concentrated = (0.0199M . 5.20L) / 11.6M → 8.89×10⁻³L

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