Answer:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.03901 mol/liter
- [Cl₂O] = 0.02351 mol/liter
Explanation:
<u />
<u>1. Chemical reaction:</u>

<u>2. Initial concentrations:</u>
i) 1.3 g H₂O
- Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol
- Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter
ii) 2.2 g Cl₂O
- Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol
- Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter
<u>3. ICE (Initial, Change, Equilibrium) table</u>

I 0.0481 0.0326 0
C -x -x +x
E 0.0481-x 0.0326-x x
<u />
<u>4. Equilibrium expression</u>
![K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}](https://tex.z-dn.net/?f=K_c%3D%5Cdfrac%7B%5BHOCl%5D%5E2%7D%7B%5BH_2O%5D.%5BCl_2O%5D%7D)

<u />
<u>5. Solve:</u>

Use the quadatic formula:

The positive result is x = 0.00909
Thus the concentrations are:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter
- [Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter
Answer:
12 liters of oxygen are released from the decomposition of the peroxide.
Explanation:
The hydrogen peroxide is decomposed by this reaction:
2 H₂O₂ (l) → 2 H₂O (l) + O₂ (g)
Molar mass H₂O₂ = 34 g/m
Moles of peroxide: 36.5 g / 34 g/m = 1.07 moles
Ratio is 2:1, so 2 moles of peroxide will be decomposed in 1 mol of oxygen (exactly the half)
1.07 moles of peroxide will be decomposed in the half of moles, 0.54 moles
Let's apply the Ideal Gases law Equation to solve the volume
1 atm . V = 0.54 mol . 0.082 .273K
V = (0.54 mol . 0.082 .273K) / 1 atm → 12L
The answer is that they havent reached their full form yet.
<span><span>1. </span><span>Fe2O3 or Iron (III)
oxide is an organic compound. It contains 3 main oxides of Iron, the iron (II)
oxide (FeO) and the iron (II, III) oxide (Fe3O4).
Now, let’s find the number of Molecules are there in 79g of Fe203:
The number of Atoms are there:
Molar Mass of Fe2O3 = 160g / mol.
=> 160g of Fe2O<span>3 </span>= 6.02 x 1023 Molecules
=> 79g of Fe2O3 = x
Next, find the value of X, in where:
x = (6.02 x 1023 x 79g) / 160g is approximately
x = 2.97 x 1023 molecules.</span></span>
Density=mass/volume=100g/20cm^3=5g/cm^3. The brick will fall in the lake, because its density is higher than that of water (1g/cm^3).