A flask contains a mixture of compounds A and B. Both compounds decompose by first-order kinetics. The half-lives are 75.00 min
for A and 10.00 min for B. If the concentrations of A and B are equal initially, how long will it take for the concentration of A to be four times that of B
1 answer:
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<u>Decimal notation:</u> 5.00
<u>Scientific notation:</u> 5.00 ×
<u>E notation:</u> 5.00e+0
<u>Answer:</u>
<u>For a:</u> The empirical formula of the compound is
<u>For b:</u> The empirical formula of the compound is
<u>Explanation:</u>
- <u>For a:</u>
We are given:
Percentage of P = 43.6 %
Percentage of O = 56.4 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of P = 43.6 g
Mass of O = 56.4 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Phosphorus =
Moles of Oxygen =
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.406 moles.
For Phosphorus =
For Oxygen =
Converting the moles in whole number ratio by multiplying it by '2', we get:
For Phosphorus =
For Oxygen =
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of P : O = 2 : 5
Hence, the empirical formula for the given compound is
- <u>For b:</u>
We are given:
Percentage of K = 28.7 %
Percentage of H = 1.5 %
Percentage of P = 22.8 %
Percentage of O = 56.4 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of K = 28.7 g
Mass of H = 1.5 g
Mass of P = 43.6 g
Mass of O = 56.4 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Potassium =
Moles of Hydrogen =
Moles of Phosphorus =
Moles of Oxygen =
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.735 moles.
For Potassium =
For Hydrogen =
For Phosphorus =
For Oxygen =
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of K : H : P : O = 1 : 2 : 1 : 4
Hence, the empirical formula for the given compound is