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Effectus [21]
3 years ago
7

A flask contains a mixture of compounds A and B. Both compounds decompose by first-order kinetics. The half-lives are 75.00 min

for A and 10.00 min for B. If the concentrations of A and B are equal initially, how long will it take for the concentration of A to be four times that of B

Chemistry
1 answer:
Shtirlitz [24]3 years ago
3 0

Answer:

how long will it take for the concentration of A to be four times that of B = 23.08mins

Explanation:

The rate law equation was applied as it relates to the half life for a first order reaction as shown in the attachment.

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PLZZZ HELP MEEEE!!!!! I WILL GIVE BRAINLIEST!!!!!!!!!
Alja [10]

Answer:

PV ∝ T

Explanation:

Charles’ law states that, at constant pressure, volume is proportional to

temperature. Gay-Lussac’s law states that, at constant volume, pressure is proportional to

temperature. Therefore, the product of pressure and volume is proportional to temperature.

This is also consistent with Boyle’s law, which states that pressure is inversely proportional

to volume when temperature is constant

Dis was easy as hell

4 0
3 years ago
If 22.5 mol of an ideal gas occupies 30.5 L at 447 K, what is the pressure of the gas?
Fantom [35]

Answer:

P = 27.07 atm

Explanation:

Given that,

The number of moles, n = 22.5 mol

Volume, V = 30.5 L

Temperature, T = 447 K

We need to find the pressure of the gas. The ideal gas law is as follows :

PV=nRT\\\\P=\dfrac{nRT}{V}

R = 0.0821 L-atm/mol-K

Put all the values,

P=\dfrac{22.5\times 0.0821\times 447}{30.5}\\\\P=27.07\ L

So, the pressure of the gas is 27.07 atm.

8 0
4 years ago
Help! Balance me those equations please:
hodyreva [135]
In balancing equations, we aim to get equal numbers of every type of atom on both sides of the equation, in order to satisfy the law of conservation of mass (which states that in a chemical reaction, every atom in the reactants is reorganised to form products, without exception). Therefore, let me walk you through question a:

<span>_Fe + _ H2SO4 --> _Fe2 (SO4)3 + _H2

First, take a stock-check of exactly what we currently have on each side (assuming that each _ represents a 1):

LHS: Fe = 1, H = 2, S = 1, O = 4
RHS: Fe = 2, H = 2, S = 3, O = 12,

There are two things to note here. Firstly, H2 (it should be subscript in reality) represents two hydrogen atoms bonded together as part of the ionic compound H2SO4 (sulphuric acid) - this two only applies to the symbol which is directly before it. Hence, H2SO4 only contains 1 sulphur atom, because the 2 applies to the hydrogen and the 4 applies to the oxygen. Secondly, the bracket before the 3 (which should also be subscript) means that there is 3 of everything within the bracket - (SO4)3 contains 3 sulphur atoms and 12 oxygen atoms (4 * 3 = 12).

Now let's start balancing. As a prerequisite, you must keep in mind that we can only add numbers in front of whole molecules, whereas it is not scientifically correct to change the little numbers (we could have two sulphuric acids instead of one, represented by 2H2SO4 (where the 2 would be a normal-sized 2 when written down), but we couldn't change H2SO4 to H3SO4).

The iron atoms can be balanced by having two iron atoms on the left-hand side instead of one:

2Fe </span>+ _ H2SO4 --> _Fe2 (SO4)3 + _H2

Now let's balance the sulphur atoms, by multiplying H2SO4 by 3:

2Fe + 3H2SO4 --> _Fe2 (SO4)3 + _H2

This has the added bonus of automatically balancing the oxygens too. This is because SO4- is an ion, which stays the same in a displacement reaction (which this one is). Take another stock check:

LHS: Fe = 2, H = 6, S = 3, O = 12
RHS: Fe = 2, H = 2, S = 3, O = 12

The only mismatch now is in the hydrogen atoms. This is simple to rectify because H2 appears on its own on the right-hand side. Just multiply H2 by 3 to finish off, and fill the third gap with a 1 because it has not been multiplied up. Alternatively, you can omit the 1 entirely:

2Fe + 3H2SO4 --> Fe2 (SO4)3 + 3H2

This is the balanced symbol equation for the displacement of hydrogen with iron in sulphuric acid.

For question b, I will just show you the stages without the explanation (I take the 3 before B2 to be a mistake, because it makes no sense to use 3B2Br6 when B2Br6 balances fine):

<span>B2 Br6 + _ HNO 3 -->_B(NO3)3 +_HBr
B2Br6 + _HNO3 --> _B(NO3)3 + 6HBr
B2Br6 + 6HNO3 --> _B(NO3)3 + 6HBr</span>
<span><span>B2Br6 + 6HNO3 --> 2B(NO3)3 + 6HBr</span>

Hopefully you can get the others now yourself. I hope this helped
</span>


8 0
3 years ago
Read 2 more answers
Chromium (VI) forms two different oxyanions, the orange dichromate ion, Cr2o72-, And the yellow chromate ion, CrO4 2-. The equil
MrRissso [65]

Answer:

See explanation

Explanation:

Let us look at the reaction again;

Cr2O7 2- (aq) + H2O(l)⇄ 2CrO4 2-(aq) + 2H^+(aq)

When we add sodium hydroxide to the system as shown, the hydroxide ion removes the hydrogen ion thereby leaving a large concentration CrO4^2-(aq) in the system this causes the solution to turn green(equilibrium position shifts to the right).

The net ionic equation is;

OH^-(aq) + H^+(aq) ----> H2O(l)

The reaction;

OH^-(aq) + H^+(aq) ----> H2O(l) is exothermic hence, if the temperature of the system is increased, the equilibrium position will shift towards the left hand side and the solution turns orange.

4 0
3 years ago
Jennifer checked the pressure in her bike tires before school and they had a pressure of 0.890 atm. She checked the tire pressur
IRINA_888 [86]

Answer:

the temperature increased outside

7 0
3 years ago
Read 2 more answers
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