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mezya [45]
3 years ago
14

What is 356g to kg? (Dimensional Analysis)

Chemistry
2 answers:
Ahat [919]3 years ago
4 0

Answer:

356 g is equal to 0.356 kg.

Explanation:

When converting grams to kilograms, just divide the mass value by 100.

Hope this helps!

aalyn [17]3 years ago
4 0

Answer:

0.356grams

Explanation:

just gotta love dimensional analysis

for one kilogram their is 1000 graMS\frac{356g}{1} =\frac{1kg}{1000g}(grams unit symbol cancel each other out)

so your left with

356kg/1000=0.356g

hope this helps!

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65% our of 20 is 13

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4 years ago
Which among the following statements is FALSE? Group of answer choices None of the above A liquid has a definite volume; but it
Vesna [10]

Answer: None of the above statements is false.

Explanation:

In a solid substance, particles are closely held together due to which a solid substance has definite shape and volume. Therefore, solids are also incompressible in nature.

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In gases, the particles are held by Vander waal forces due to which they move rapidly from one place to another. Hence, gases are highly compressible in nature.

Thus, we can conclude that none of the given statements are false.

4 0
3 years ago
If there are 94 different kinds of naturally occurring atoms how many different naturally occurring elements are there?
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Answer:

118 elements

Explanation:

Of these 118 elements, 94 occur naturally on Earth.

7 0
3 years ago
If you mixed three Dixie cups’ contents together containing 0.05L of 1.0M lemonade, 0.05L of 2.5M lemonade, and 0.05L of 0.5M le
viva [34]

Molarity of the resulting solution will be 1.33 M.

<u>Explanation:</u>

First we have to find the number of moles for each of the solution using the formula, moles = molarity × volume

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For cup 2 = 2.5 M × 0.05 L= 0.125 moles

For cup 3 = 0.5 M × 0.05 L = 0.025 moles

Total moles = 0.05 + 0.125 + 0.025  = 0.2 moles

We have to find the total volume as, 0.05 + 0.05 + 0.05 = 0.15 L

Now we have to find the molarity as, moles / volume = 0.2 moles/ 0.15 L = 1.33 M

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Answer:

Negative ion

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I took the test

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