The answer to your problem, I’m pretty sure the second one, I’m not to sure tho!
Answer:
3.s is 3 times the age of Sydney's which is equals to Luke age + 5
Step-by-step explanation:
Given Sydney’s age, s
and also Luke is 5 years younger than 3 times Sydney’s age.
Sydney's 3 times age is 3.s
Luke age = Sydney's 3 times age - 5
Luke age=3.s-5 ⇒ 3.s = Luke age + 5
Hence, 3.s is 3 times the age of Sydney's which is equals to Luke age + 5
Answer:
Step-by-step explanation:
f(x) = 2x - 3
f(-2) = 2(-2) -3 = -4 - 3 = -7
f(-1) = 2(-1) -3 = -2 - 3 = - 5
f(0) = 2(0) -3 = 0 - 3 = -3
f(1) = 2(1) -3 = 2 - 3 = -1
f(2) = 2(2) -3 = 4 - 3 = 1
f(3) = 2(3) -3 = 6 - 3 = 3
Answer:
$7075 or 7718
Step-by-step explanation:
91100-6200=84900
84900/11= 7718.18181818 or rounded= 7718
(This is if the december month doesnt count.)
84900/12=7075
(If december is included.)
Answer:
We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Step-by-step explanation:
We know that the perimeter of a rectangle = 2(l+w)
i.e.
P = 2(l+w)
Here
Given that the length and width of the playground by a scale factor of 2
A scale factor of 2 means we need to multiply both length and width by 2.
i.e
P = 2× 2(l+w)
P' = 2 (2(l+w))
= 2P ∵ P = 2(l+w)
Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
