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likoan [24]
3 years ago
6

The function f(x)=(25)x is shown on the coordinate plane.

Mathematics
2 answers:
Tpy6a [65]3 years ago
4 0

Answer:

<h3>In the right end, as x increases without bound, the graph of f(x) decreases.</h3><h3>In the left end, as x decreases without bound, the graph of f(x) increases.</h3>

Step-by-step explanation:

According to the graph, the end behaviour of the function in the image is decreasing without bound. When we graph a function, with put an arrow to indicate when a function increases or decreases without bound, that's why in this case we can say the decreases without bound, the function extends without limit.

Therefore, as the <em>x </em>increases, <em>f(x) </em>decreases. If you carefully pay attention to the graph, <em>x </em>is constantly increasing in the right end, and <em>f(x) </em>is more and more close to the <em>x-axis.</em>

andre [41]3 years ago
3 0
It is a straight line


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What is the y-intercept of the graph of the line whose equation is y=3/4x+1
Tanzania [10]

Answer:

The correct answer is "1".

Step-by-step explanation:

You need only set x to zero, and solve for y:

y = \frac{3}{4} x + 1\\y = \frac{3}{4}0 + 1\\y = 1

4 0
3 years ago
Boris pushes a 5 lb. box 6 feet in 2 seconds. He has _____.
andre [41]

Answer:

B.

Step-by-step explanation:

3 0
3 years ago
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Ok if you have 734
White raven [17]
The answer you will need is seven hop I was helpful do me a favor and click on thank on the bottom
5 0
3 years ago
Find angle D if angle B = 50
Mariana [72]
<h3>Answer:  80 degrees</h3>

============================================================

Explanation:

I'm assuming that segments AD and CD are tangents to the circle.

We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.

By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.

----------------------------

Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.

Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.

We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.

---------------------------

Here's what we have so far for quadrilateral DAEC

  • angle A = 90
  • angle E = 100
  • angle C = 90
  • angle D = unknown

Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees

A+E+C+D = 360

90+100+90+D = 360

D+280 = 360

D = 360-280

D = 80

Or a shortcut you can take is to realize that angles E and D are supplementary

E+D = 180

100+D = 180

D = 180-100

D = 80

This only works if AD and CD are tangents.

Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.

5 0
3 years ago
Its worth helping xd
nata0808 [166]

Answer:

c)\ 2\frac{4}{10}

Step-by-step explanation:

5\frac{1}{5}-2\frac{8}{10}  \\\\5\frac{2}{10}-2\frac{8}{10}  \\\\\frac{52}{10}-\frac{28}{10} \\\\ \frac{24}{10} \\\\2\frac{4}{10}

Hope this helps!

7 0
3 years ago
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