Step-by-step explanation:
1) Your problem → (4x^2 - 17x^3 + 9) - (x^2 + 9x + 23x^2 + 11)
(-17x^3+4x^2+9)-(x^2+23x^2+9x+11)
=-17x^3+4x^2+9-x^2-23x^2-9x-11
=-17x^3+4x^2-x^2-23x^2-9x+9-11
=-17x^3-20x^2-9x-2
2) Your problem → 0 - 19.73 - 25x^2 - 12x - 3
=0-19.73-25x2-12x-3
=-25x^2-12x-22.73
3) - 10.x^3 – 162x^2 – 24x - 4
4) Your problem → 17x^3 - 20x^2 - 9x^2
=17x^3-20x^2-9x^2
=17x^3-29x^2
5) -16x^3 – 243x^2 – 12x – 3
1 mile * (1 hr / 4 mile) = 1/4 hr
1/4 hr = 15 min
all you have got to do is make a table and in the top put x bottom the numbers that go up are x and the others are y in the table just write down the numbers needed
System of Equations
Let:
x = number of people that can be seated at a table
y = number of people that can be seated at a booth
The first plan consists of 23 tables and 10 booths and then 228 people could be seated, thus:
23x + 10y = 228
The second plan consists of 12 tables and 12 booths and that way 180 people could be seated, thus:
12x + 12y = 180
The method of elimination requires equating the coefficients of one variable and eliminating it by adding the equations.
Multiply the first equation by 12:
276x + 120y = 2736
Multiply the second equation by -23:
-276x - 276y = -4140
Add the last two equations (the variable x cancels out):
120y - 276y = 2736 - 4140
Simplifying:
-156y = -1404
Dividing by -156:
y = -1404/(-156)
y = 9
Substitute this value in the first equation:
23x + 10(9) = 228
Operate:
23x + 90 = 228
Subtract 90:
23x = 138
Divide by 23:
x = 138/23
x = 6
Every table can seat 6 people, and every booth can seat 9 people