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adoni [48]
3 years ago
6

Solve and show your work for each question a). B). C).

Mathematics
1 answer:
Andreyy893 years ago
6 0

Answer:

Step-by-step explanation:

a) Here, the first term is .48 and the common ratio is 1/100 (since each new 48 is 1/100 th of the previous 48).                                   a

Use the formula s = sum of geometric series = -----------

                                                                                  1 - r

                                           0.48              48

which in this case is s = --------------- = ------------ = 48/99 = 16/33

                                          1 - 1/100        100 - 1

Check this result by finding 16/33 on a calculator.  Is the result equal to 0.484848484848.... ?  Yes

b) Here we have the bar over the 8 only.  0.48 with the bar over the 8 is equivalent to 0.4888888888 ...

                                                              0.08

or 0.4 + 0.0888888888 ...      or 0.4 + ------------

                                                                1 - 1/10

                                             

                                              0.08                       8

and this simplifies to 0.4 + ------------  =  0.4 + ---------

                                                9/10                      90

Evaluating this last result on a calculator results in 0.488888888 ...

c)  0.48 expressed as a fraction is  48/100 = 12/25

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Answer:

These triangles cannot be proved congruent

Step-by-step explanation:

The theorems for congruence are  SSS SAS ASA AAS. Here, there is only one common side and one common angle marked, therefore you cannot prove congruency.

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2 years ago
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What is the slope that passes through the points : (-2,9) and (4,-7)
Westkost [7]

Use the slope formula below:

\large \boxed{m =  \frac{y_2 - y_1}{x_2 - x_1} }

The m-term represents the slope.

The formula is the changes of two y-points over the changes of two x-points. We are given two points. Substitute both points in the formula.

\large{m =  \frac{9 - ( - 7)}{ - 2 - 4} } \\  \large{m =  \frac{9 + 7}{ - 6}  \longrightarrow  \frac{16}{ - 6} } \\  \large{m =  \frac{8}{ -3 }  \longrightarrow  -  \frac{8}{3} }

Therefore the slope is -8/3

Answer

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Hope this helps! Let me know if you have any doubts.

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Rosita earns money by walking dogs after school and on weekends.She walks Madeline every other day,buddy every fourth day,and er
leonid [27]

On 12th day Rosita will walk all three dogs

<em><u>Solution:</u></em>

Given that Rosita earns money by walking dogs after school and on weekends

She walks Madeline every other day,buddy every fourth day,and ernie every third day

Today she walked all three dogs

<em><u>To find: the day when she walked all three dogs</u></em>

From given question,

Madeline is walked every other day means every two days:  2

Buddy is walked every fourth day:  4

Ernie is walked every third day:  3

To find the day when she walked all three dogs, we have to find the least common multiple (LCM) of 2, 4, 3

<em><u>L.C.M of 2, 4, 3:</u></em>

List all prime factors for each number

Prime Factorization of 2 shows:

2 is prime  => 2^1

Prime Factorization of 3 shows:

3 is prime  => 3^1

Prime Factorization of 4 is:

2 \times 2 = 2^2

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 3

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 3 = 12

Thus on 12th day Rosita will walk all three dogs

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4 years ago
Student scores on exams given by a certain instructor have mean 74 and standard deviation 14. This instructor is about to give t
Lapatulllka [165]

Answer:

P(\bar X >80)=P(Z>2.143)=1-P(z

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable that represent the Student scores on exams given by a certain instructor, we know that X have the following distribution:

X \sim N(\mu=74, \sigma=14)

The sampling distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

The deduction is explained below we have this:

E(\bar X)= E(\sum_{i=1}^{n}\frac{x_i}{n})= \sum_{i=1}^n \frac{E(x_i)}{n}= \frac{n\mu}{n}=\mu

Var(\bar X)=Var(\sum_{i=1}^{n}\frac{x_i}{n})= \frac{1}{n^2}\sum_{i=1}^n Var(x_i)

Since the variance for each individual observation is Var(x_i)=\sigma^2 then:

Var(\bar X)=\frac{n \sigma^2}{n^2}=\frac{\sigma}{n}

And then for this special case:

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P(\bar X >80)

And we have already found the probability distribution for the sample mean on part a. So on this case we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

Applying this we have the following result:

P(\bar X >80)=P(Z>\frac{80-74}{\frac{14}{\sqrt{25}}})=P(Z>2.143)

And using the normal standard distribution, Excel or a calculator we find this:

P(Z>2.143)=1-P(z

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Answer:

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