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aleksandr82 [10.1K]
3 years ago
14

Use the correct order of operation to solve the following problem 3x (50 - 6^2) ÷ 2 =

Mathematics
1 answer:
Effectus [21]3 years ago
6 0

Answer: 21

Step-by-step explanation:

Ok so first of all the numbers in the parentheses go first.

So 6 to the power of 2 (6^2) would be 6x6 which equals 36

50-36=14

After that you just keep rewriting the problem after every step.

Since the 3 is outside of the parentheses, you would multiply it with the 14

3x14=42

Finally 42÷ 2=21

3x (50 - 6^2) ÷ 2 =

        3(14)÷ 2

           42÷ 2= <u><em>21</em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>Hope this helps (:</em></u>

<u><em>Btw sorry if it's a bit confusing but the answer is 21</em></u>

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Answer:

x = 2

Step-by-step explanation:

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What is the ratio of y to x? Without extending the table, what would the value for y be when x = 54?
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3 years ago
X<br> 8<br> 17<br> Find the exact value of x.<br> X=
Furkat [3]

Answer:

621

629

Step-by-step explanation:

We know that

sin

(

x

+

y

)

=

sin

x

cos

y

+

sin

y

cos

x

If

cos

x

=

8

17

and

sin

y

=

12

37

We can use,

cos

2

x

+

sin

2

x

=

1

and

cos

2

y

+

sin

2

y

=

1

To calculate

sin

x

and

cos

y

sin

2

x

=

1

−

cos

2

x

=

1

−

(

8

17

)

2

=

225

17

2

sin

x

=

15

17

cos

2

y

=

1

−

sin

2

y

=

1

−

(

12

37

)

2

=

1225

37

2

cos

y

=

35

37

so,

sin

(

x

+

y

)

=

15

17

⋅

35

37

+

12

37

⋅

8

17

=

621

629

Answer link

Shwetank Mauria

Nov 22, 2016

sin

(

x

+

y

)

=

621

629

or

−

429

629

depending on the quadrant in which sine and cosine lie.

Explanation:

Before we commence further, it may be mentioned that as

cos

x

=

8

17

,

x

is in

Q

1

or

Q

4

i.e.

sin

x

could be positive or negative and as

sin

y

=

12

37

,

y

is in

Q

1

or

Q

2

i.e.

cos

y

could be positive or negative.

Hence four combinations for

(

x

+

y

)

are there and for

sin

(

x

+

y

)

=

sin

x

cos

y

+

cos

x

sin

y

, there are four possibilities.

Now as

cos

x

=

8

17

,

sin

x

=

√

1

−

(

8

17

)

2

=

√

1

−

64

289

=

√

225

289

=

±

15

17

and

as

sin

y

=

12

37

,

cos

y

=

√

1

−

(

12

37

)

2

=

√

1

−

144

1369

=

√

1225

1369

=

±

35

37

Hence,

(1) when

x

and

y

are in

Q

1

sin

(

x

+

y

)

=

15

17

×

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(2) when

x

is in

Q

1

and

y

is in

Q

2

sin

(

x

+

y

)

=

15

17

×

−

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

(3) when

x

is in

Q

4

and

y

is in

Q

2

sin

(

x

+

y

)

=

−

15

17

×

−

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(4) when

x

is in

Q

4

and

y

is in

Q

1

sin

(

x

+

y

)

=

−

15

17

×

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

Hence,

sin

(

x

+

y

)

=

621

629

or

−

429

629

7 0
3 years ago
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