we can always find the x-intercept by simply settting y = 0, and solving for "x".
and we can always find the y-intercept by simply setting x = 0 and solving for "y".
![\bf x-4y=-16\implies \stackrel{x=0}{0-4y=-16}\implies y=\cfrac{-16}{-4}\implies y=4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (0,4)~\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20x-4y%3D-16%5Cimplies%20%5Cstackrel%7Bx%3D0%7D%7B0-4y%3D-16%7D%5Cimplies%20y%3D%5Ccfrac%7B-16%7D%7B-4%7D%5Cimplies%20y%3D4%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%280%2C4%29~%5Chfill%20)
(x+3)/2x+5 + (3x-5)/(3x+5)
LCM = ( 2x+5)( 3x+5)
[( x+3)( 3x+5) + ( 3x -5)( 2x+5)]/( 2x+5)( 3x+5)
= (3x^2 + 5x +9 x +15 + 6x^2 + 15x -10x -25)/( 2x+5)( 3x+5)
=( 9 x^2 + 19x -10)/( 2x +5)(3x+5)
A) option
Answer:
for this equation one factor is (x+6) and the other is (x-4)
I thinkit would be 14 Minutes, Im not sure though.
5x - 20 = 8x - 65
-20 = 3x - 65
3x = 45
x = 15