-6 answer to -4+(-2)
3 answer to 7+(-4)
Answer:
breads
Step-by-step explanation:
idk
Answer:
1)Mean=920 $
2)Standard Error =S.E.=38
3)more likely to take place Event 25 studio apartments with a mean rent between $901 and $939
Step-by-step explanation:
Given:
True mean =920 $
S.D=190 $
No .of samples=25
To Find:
1)Mean of sample.
2)S.E
Solution:
Now , the mean for given sample distribution is given as 920 $
Hence Mean =920 $
Now calculating the Standard error
S.E.= S.D./Sqrt(n)
=190/Sqrt(25)
=190/5
=38
Therefore the Standard error is about 38 .
a) When n=1 then P(901≤X≤939)
So,
Z1=(901 -920)/190/Sqrt(1)]
Z1=-0.1
Z2=(939-920)/(190/Sqrt(1)]
Z2=0.1
So
Pr(-0.1≤Z≤0.1)=P(Z≤0.1)-P(Z≤-0.1)
=0.5398-0.4602
=0.0797 % chance of the sample distribution
b)n=25 then P(901≤X≤939)
Z1=(901-920)/S.E
Z1=-19/38=
Z1=-0.5
And Z2=0.5
So,
Pr(-0.5≤Z≤0.5)
=Pr(Z≤0.5)-Pr(Z≤-0.5)
=0.6915-0.3085
=0.3829
i.e 38.29 % chance of the sample distribution
Hence More likely to take place will be a sample of 25 studio apartments with a mean rent between $901 and $939.
0.3829>0.0797.
Because the probability of causing above event is more than the option A.
