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Sloan [31]
3 years ago
11

Do yall know any easy way to do slope​

Mathematics
2 answers:
mart [117]3 years ago
7 0

Answer:

To find the slope of two given points, you can use the point-slope formula of (y2 - y1) / (x2 - x1). With the points plugged in, the formula looks like (3 - 2) / (4 - 1). Simplify the formula to get a slope of ⅓.

Step-by-step explanation:

Mumz [18]3 years ago
7 0
Find the x or y axis . And make a foldable that can help you find the slopes with the formula
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Write the expression as a power and evaluate 2^6 *4 <br> WILL AWARD BRAINLIEST!!!
ipn [44]

Answer:

{2}^{6} \times 4  =  {2}^{6}  \times  {2}^{2}

According to the laws of indices, when multiplying numbers with exponents and the bases are the same add the powers

=  {2}^{6 + 2}

= {2}^{8}

= 256

7 0
3 years ago
Describe one way to find the area of the figure below, given the dimensions. Solve for a challenge
tigry1 [53]

Answer:

OK so you didnt put which numbers, but here is how you solve for area. Say if the legnth is 4 and the widght is 6. you have to do legnth times witgh, it this case 6x4 area is 24. Lxw=a

Step-by-step explanation:

8 0
3 years ago
If a and b are both positive, two-digit integers, is a + b a multiple of 11? The tens digit of a is equal to the units digit of
Serhud [2]

Answer:

Yes!

Step-by-step explanation:

Let x be the tens place and y be the units place. x and y need to be odd because in other case a or b will not be odd. For example, if x=1 and y=2 a will be 21 but b will be 12 that is not odd.

Now, a+b = xy+yx. Note that xy is not x*y, is just the digits concatenated.Then, there are two cases:

If x+y<10 then xy+yx = (x+y)(x+y) (again, that is not a multiplication is x+y concatenated with x+y) and that is 11*(x+y) a multiple of 11.

If x+y≥10 then xy+yx = (x+y+1)(x+y-10) because x+y<20.

Now we are going to see that last result without the concatenation, as a sum, that is

(x+y+1)*10 + x+y-10 = 10x+10y+10+x+y-10 = 11x+11y = 11(x+y). This result is clearly a multiple of 11.

In conclusion, in all cases the result of a+b is a multiple of 11.

6 0
3 years ago
Which congruence theorem can be used to prove △BDA ≅ △DBC? Triangles B D A and D B C share side D B. Angles C B D and A D B are
Tomtit [17]

Answer:

A. Hypotenuse-leg (HL) congruence.

HL, when you have 2 right triangles and their hypotenuses are congruent you are able to say HL

Step-by-step explanation:

We know that the hypotenuse-leg theorem states that if the hypotenuse and one leg of a right triangle are congruent to hypotenuse and corresponding leg of another right triangle, then the triangles are congruent.  

hypotenuse(AB) of △BDA equals to hypotenuse (CD) of △DBC.  

BDA and DBC share a common side DB.

Using Pythagorean theorem we will get,

CD^{2}=DB^{2}+BC^{2}...(1)  \\\\AB^{2}=DB^{2}+AD^{2}...(2)

We have been given that CD=AB, Upon using this information we will get,

DB^{2}+BC^{2}=DB^{2}+AD^{2}

Upon subtracting DB^{2} from both sides of our equation we will get,

BC^{2}=AD^{2}\\\\BC=AD

<h3>Therefore, by HL congruence △BDA ≅ △DBC.</h3>
6 0
3 years ago
Read 2 more answers
What is the simplified value of the expression below?
Irina-Kira [14]
The answer would be C. 15.52
4 0
3 years ago
Read 2 more answers
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