A. It is an experiment as the sales director is applying treatment ( the training ) to a group and recording the results.
B. I would have 250 sales representatives from each region take the training and 250 from each region to not take it so i can be able to see if it affects both regions differently. The representatives from each region would be chosen at random and the length of their training would be the same for all.
C. now you would only be able to have 200 people from each region train. this would lower the percentage of the impact the training had on the amount of sales ( if any) . For example, if the original 250 trained people in a region increased the sales in that region by 20 percent and 50 of those people ended up not actually training, the sales would have only increased by 16 percent.
D. correlational research is best to establish causality. for example, the amount of training the representatives got may affect how much they are able to sell. also the number of representatives trained may affect the amount sold
Answer:
its c
Step-by-step explanation:
<span>b. 60 m2
</span>Find the area of the figure. Assume all figures are made up of parallelograms and triangles.
NOT:
b. 60 m2
c. 108 m2
<span>d. 135 m2 please help</span>
<span>
</span>
ANSWER

EXPLANATION
Let R be the radius of the bigger circle and r, be the radius of the smaller circle.
Then their ratio is given as,

We can rewrite it as fractions to get,

We make R the subject to get,

The area of the bigger circle can be found using the formula,

This implies that,


But it was given in the question that, the area of the bigger circle is 27π.

We divide through by 9π to get,

This means that,

The area of the smaller circle is therefore

Answer: 800 x 1.033^4 = 910.94 (result is rounded)
Step-by-step explanation: