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CaHeK987 [17]
2 years ago
8

Expert Help: Carlos has equal numbers of classical songs, country

Mathematics
1 answer:
motikmotik2 years ago
4 0

Answer:

cool you have your awnser

Step-by-step explanation:

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3n + 14= --4 What is the answer
andre [41]

Answer: n = -6

Step-by-step explanation:

3n+14=-4

Subtract 14 from both sides.

3n+14-14=-4-14

Simplify

3n=-18

Divide both sides by 3

3n/3 = -18/3

n=-6

5 0
2 years ago
Read 2 more answers
I need to know how to do this step my step and the answer
MissTica
You can use the calculator or 0^2 is 0 x -3 =0 +7 (0) -4 =-4
5 0
3 years ago
HELP ASAP! Which equation represents a linear function that has a slope of 4/5 and a y-intercept of -6?
vivado [14]
The answer is c explained d a bcdadeadcdadcddacda
8 0
3 years ago
Find the area of the shaded figure below. Use 3.14 for pi. NO LINKS OR IMPROPER ANSWERS
Lapatulllka [165]

Answer:

The area of the shaded region is about 58.9 square inches.

Step-by-step explanation:

To solve this question, let's recall some facts.

We know that the area of a circle can be defined as the following:

A = \pi r^2

where r is the radius of the circle.

We too know that circles have a diameter and a radius. The diameter of a circle is the distance a line that connects two points on a circle with its center, and the radius is half of the diameter.

We also know that figures can touch each other, or be in tangent with each other. For the sake of simplicity, we're going to assume that the shaded circles are in tangent with each other, or touch each other. Because they touch each other, these three circles can share 5 in. of the 15 in. rectangle. This means that the circles are 5 in. in diameter, or 2.5 in in radius.

Now, we can solve the problem.

Because we have 3 circles, each with 2.5 in. radii, we can have the following expression which represents the total area of these circles:

3*\pi (2.5)^2

= 3*3.14(2.5)^2

= 3 *3.14 *6.25

= 58.875

After approximation, I can conclude that the area of the shaded region is 58.9 square inches.

6 0
2 years ago
What is the value of p+q
Korvikt [17]

ax^2+bx+c=0\\\\x_1,\ x_2-solutions\\\\x_1+x_2=\dfrac{-b}{a}\\--------------------------\\\\4x^2-7x-2=0\\\\a=4,\ b=-7,\ c=-2\\\\p,\ q-solutions\\\\p+q=\dfrac{-(-7)}{4}=\dfrac{7}{4}

6 0
3 years ago
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